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White raven [17]
4 years ago
9

How do I solve 2x³a³ over 5x⁻³a² multiplied by 5x⁻⁴a over 3x²a⁻⁵ ?

Mathematics
1 answer:
gulaghasi [49]4 years ago
7 0
\frac{2x^3a^3}{5x^{-3}a^2}\cdot\frac{5x^{-4}a}{3x^2a^{-5}}=\frac{2x^{3-4}a^{3+1}}{3x^{-3+2}a^{2-5}}=\frac{2x^{-1}a^4}{3x^{-1}a^{-3}}=\frac{2}{3}a^{4-(-3)}=\frac{2}{3}a^7
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Use substitution to solve the<br> following system of equations.<br> 9x + 5y = 32 AND y = -3x + 4
Darya [45]

Answer:

x = -2

y = 10

Step-by-step explanation:

Since they already gave y as -3x +4, you will then have to substitute that amount into the formula

9x + 5y = 32

By doing that you get

9x +5(-3x+4) = 32

9x -15x +20 = 32

Then, you ill take 20 to the other side to subtract 32, which will get you

-6x = 12

Then, you will get x = -2

Then substitute that for the equation

y = -3x + 4

You will get

y = -3(-2) + 4,

You will get y as 10

SO then your final answer is x = -2, y = 10

4 0
3 years ago
Dlane's shop sells 5 quarts of ice cream each day. How much is this in pints?
Vikentia [17]

Answer:

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Step-by-step explanation:

1 qt = 2 pt

5 0
3 years ago
Given: MzQVR = 49°
faust18 [17]

Answer:

4. Vertical angles theorem

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Step-by-step explanation:

3 0
3 years ago
Help plsssssssssssss
jonny [76]

Answer:

144

Step-by-step explanation:

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7 0
3 years ago
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Angle pwm is equal to angle pkm
Len [333]
<h3>Answer: 24 (choice C)</h3>

Assuming M is a midpoint of KW, this means that WM and KM are congruent

WM = KM

x+3 = 2(x-3) ... substitution

x+3 = 2x-6

2x-6 = x+3

2x-6-x = x+3-x .... subtract x from both sides

x-6 = 3

x-6+6 = 3+6 ... add 6 to both sides

x = 9

Use x = 9 to find the length of WM

WM = x+3 = 9+3 = 12

Which can be used to find the length of KM as well

KM = 2(x-3) = 2(9-3) = 2(6) = 12

both lengths are the same (12) as expected

This makes WK to be

WK = WM + KM

WK = 12 + 12

WK = 24

3 0
3 years ago
Read 2 more answers
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