Question

How do I solve 2x³a³ over 5x⁻³a² multiplied by 5x⁻⁴a over 3x²a⁻⁵ ?

Answer 1

$\frac{2x^3a^3}{5x^{-3}a^2}\cdot\frac{5x^{-4}a}{3x^2a^{-5}}=\frac{2x^{3-4}a^{3+1}}{3x^{-3+2}a^{2-5}}=\frac{2x^{-1}a^4}{3x^{-1}a^{-3}}=\frac{2}{3}a^{4-(-3)}=\frac{2}{3}a^7$