Question

What is the area of this figure?

Answer 1

First of all we can draw a parallel line to divide the figure into a triangle and a rectangle as shown in the figure. To find the area of our rectangle, remember that the area of a rectangle is length times width, so $A_{r} =lw$. Since we know for our figure that the length and width of our rectangle are 13cm and 6cm respectively, lets replace those values in our formula to get its area:
$A _{r} =(13cm)(6cm)$
$A=78cm^{2}$
Similarly, the area of a triangle is one half times base times height, so $At=( \frac{1}{2})bh$. Since we know that our base is 8cm and our height 6cm, lets replace those values in our equation to find the area of our triangle:
$A_{t} =( \frac{1}{2})(8cm)(6cm)$
$A_{t} =24cm^{2}$

Now the only thing left is add our areas:
 $A_{total} =78cm^{2}+24cm^{2} =102cm^{2}$

We can conclude that the correct answer is A. 102