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mars1129 [50]
3 years ago
14

Plz help will give brainliest

Mathematics
2 answers:
denis23 [38]3 years ago
7 0
The answer for this question is A
PilotLPTM [1.2K]3 years ago
4 0

Step-by-step explanation:

Hey there!!!!

Your required answer is option A.

The reason is.

When we solve it through elimination method we need to multiply second equation by "2" and then subtract to get "-4y" in 1st equation and "+4y" in 2nd equation cancelled.(As when we multiply equation 2 by 2 and subtract we get "-2y" as "+4y".)

So, it the equation seems like,

12 {x}^{2}  + 4 {y}^{2}  = 22

Now, this equation is made after multiplying it by 2 and subtracting the 1st and 2nd equation to solve the equation s.

So, the answer is option A.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Determine whether the set, together with the indicated operations, is a vector space. If it is not, then identify one of the vec
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Answer:

The answer to the question are

(B) The set is not a vector space because it is not closed under addition. and

(D) The set is not a vector space because an additive inverse does not exist.

Step-by-step explanation:

To be able to identify the possible things that can affect a possible vector space one would have to practice on several exercises.

The vector space axioms that failed are as follows

(B) The set is not a vector space because it is not closed under addition.

(2·x⁸ + 3·x) + (-2·x⁸ +x) = 4·x which is not an eighth degree polynomial

(D) The set is not a vector space because an additive inverse does not exist.

There is no eight degree polynomial  = 0

The axioms for real vector space are

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7 0
3 years ago
Given cscx/cotx=sqrt2, find a numerical value of one trigonometric function of x.
Firlakuza [10]

   \frac{csc (x)}{cot (x)} = \sqrt{2}

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⇒ cos (x) = \frac{\sqrt{2}}{2}

Use the Unit Circle to determine when cos (x) = \frac{\sqrt{2}}{2}

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3 years ago
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How do you simplify number 6?
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4 0
3 years ago
I’m just stuck on #6, is it d or c???
QveST [7]

Answer:

It is D, D sounds reasonable.

---------------------------------------------------------------------------------------------------------------

sorry if that was no help at all

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Answer:

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