Answer:
a) 50S + 30C ≤ 800
b) 1) MAX = S + C
2) Max = 0.03S + 0.05C
3) Max = 6S + 5C
Step-by-step explanation:
Given:
Total space = 800 square feet
Each sofa = 50 square feet
Each chair = 30 square feet
At least 5 sofas and 5 chairs are to be displayed.
a) Write a mathematical model representing the store's constraints:
Let S denote number of sofas displayed and C denote number of chairs displayed.
The mathematical model will be:
50S + 30C ≤ 800
At least 5 sofas are to be dispayed: S ≥ 5
At least 5 chairs are to be displayed: C ≥ 5
b)
1) Maximize the total pieces of furniture displayed:
S + C = MAX
2) Maximize the total expected number of daily sales:
MAX = 0.03S + 0.05C
3) Maximize the total expected daily profit:
Given:
Profit on sofas = $200
Profit on chairs = $100
Max Expected daily profit =
Max = (200S * 0.03) + (100C * 0.05)
<em>Max = 6S + 5C</em>
75 dollars who doesn't know that
He needs to buy 198 tiles. To find this, break down the dimensions of the room from feet into inches then divide each number(264in and 192in) by 16in. This gives you 16.5 by 12 tiles. Now multiply 16.5 by 12 and you have your total number of tiles.
134,500 rounded is 13,000
2 2/5 per day I’m pretty sure ( 3 1/8 / 7 1/2)
