Answer:
Attached diagram A'B'C'D'
Step-by-step explanation:
Given is a quadrilateral ABCD. It says to draw a dilated version with a scale factor 2/3.
We see that scale factor is less than 1 which means it shrinks the image to a smaller one.
To draw a scaled copy, we need to find the lengths of its sides.
To do so, we can draw the diagonals AC & BD, and they intersect at origin O(0,0) such that OA= -2, OB= 2, OC= 4, OD= -4.
Applying a scale factor of 2/3, we get OA' = -4/3, OB' = 4/3, OC' = 8/3, OD' = -8/3.
So we have attached a scaled copy A'B'C'D' of quadrilateral ABCD with a scale factor 2/3.
Answer:
D. Linear
The answer is negative linear, because when it incresing from 0 to 1 to 2 to 3 (year) it always deacreasing in the value($).
A²+b²=c²
64+b²=196
b²=132
b=11.48912529
Answer:
x ≠ 4 or -2
Step-by-step explanation:
the denominator cannot be zero, so factor the bottom equation to get the zeros and those are the domain restrictions.
3x^2 - 6x - 24 ≠ 0
3(x^2 - 2x - 8) ≠ 0 (factor out a 3)
3(x - 4)(x + 2) ≠ 0 (factor equation)
x ≠ 4, x ≠ -2 (use zero product property to find zeros)
7 girls on a bus, each has two legs. 7 * 2 = 14.
Each girl has 7 backpacks. So 7 * 7 = 49.
49 * 7 = 343 cats in total
343 * 4 = 1,372 cat legs.
343 * 7 = 2401 small cats
2401 * 4 = 9,604 cat legs
14 + 1,372 + 2,401, + 9,604 = 10,990 legs in total
