Answer:
840 breads size oven.
Explanation:
According to Little's law,
Inventory = flow rate × flow time
Inventory (I) is the number of flow units that are currently handled by a business process.
I= unknown
Flow rate (R) is the number of flow units going through the business process per unit time.
R= 4200 breads per hour or 70 breads per minute (4200/60)
Flow time (T) is the amount of time a flow unit spends in a business process from beginning to end.
T= 12 minutes.
Inventory = flow rate × flow time
Inventory = 70 breads per minute × 12 minutes
Inventory = 840 breads size oven
Therefore, for the company to produce 4200 breads per minute, 840 breads size oven is required.
Sally works for Timber Products, Inc. The basis for her contribution under the Federal Insurance Contribution Act to help pay for benefits that will partially make up for her loss of income on retirement is her annual wage base.
Answer: Option B
<u>Explanation:</u>
The contribution that Sally, who is working for Timber Products incorporation, has to make for federal insurance contribution act is based on the amount of wage that Sally gets on an annual basis or the wage that she gets in a year.
A part of that wage which is a particular percentage is paid to the federal insurance contribution act who is going to benefit her in case she incurs any kind of loss of income.
Answer:
$1,375
Explanation:
Given the information above, the Ending inventory = Units available - Units sold
Units available = 10 + 25 + 30 + 70 = 80
Units sold = 60
Ending inventory = 80 - 60
Ending inventory = 20
Cost of ending inventory under FIFO
= (15 × $70) + (20 - 15) × $65
= $1,050 + $325
= $1,375
Therefore, the ending inventory cost using FIFO is $1,375
Answer:
4.28 grams
Explanation:
The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by the formula:

Given that:
P(x > 5.1 grams) = 5%, x = 5.1 grams, σ = 0.5 grams
P(x > 5.1 grams) = 5%
P(x < 5.1 grams) = 100% - 5% = 95%
P(x < 5.1) = 95%
From the normal distribution table, 95% corresponds with a z score of 1.645. Hence:
