15,17,19
Suppose the three odd integers are #n#, #n+2# and #n+4#
Their sum is:
#n + (n+2) + (n+4) = 3n+6#
#13# more than twice the largest of the three is:
#2(n+4)+13 = 2n+21#
From what we are told these two are equal:
#3n+6 = 2n+21#
Subtract #2n+6# from both sides to get:
#n = 15#
So the three integers are:
#15, 17, 19#
3/10 is the answer because 30/100
Devide both by 10 and poof there's the answer!
Answer:
1/6
Step-by-step explanation:
landing on heads is a 1/2% and landing on a 3 or 4 is a 1/3 then multiply together
Answer:
10x² - 48y² - 11x + 2y - 74xy
Step-by-step explanation:
(-x+8y)+(-10x-6y)(−x+8y)+(−10x−6y)
Rearranging,
=> - x - 10 x + 8y - 6y + (-10x-6y)(−x+8y)
=> - 11x + 2y + 10x² - 48y² + 6xy - 80xy
=> 10x² - 48y² - 11x + 2y - 74xy
Answer:
g
Step-by-step explanation:
(-6+8)/2=1 or g
idk if that helps
