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Ulleksa [173]
4 years ago
10

Please answer correctly.

Mathematics
1 answer:
Murljashka [212]4 years ago
3 0

In order to find the amount left after both sisters ate the cereal, we have to add the amount of cereal the two sisters ate.

Katrina ate 1 3/4 and her sister ate 7/8.

(1 3/4 + 7/8)

(you put a parentheses around it so that you add the two first before subtracting it from the original amount)

Then, we would subtract it from the original amount: 12 1/2.

-> The equation would be: 12 1/2 - (1 3/4 - 7/8).

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Step-by-step explanation:


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New heat lamps are reported to have the mean lifespan of 100 hours with a standard deviation of 15 hours. Before replacing their
Tom [10]

Answer:

1

  The  correct option is  C

2

 The  correct option is C

3

The  correct option is A

4

The  correct option is B

Step-by-step explanation:

From the question we are told that

    The  population mean is  \mu =  100

     The  standard deviation is  \sigma  =  15

     The  sample size is  n  =  36

     The  sample mean is  \=  x =  105.1

Generally

    The  null hypothesis is  H_o:  \mu =  100 \  hours

     The  alternative hypothesis is  H_a  :  \mu  \ne  100\ hours

Given that the null hypothesis is  true then the  distribution of sample means  \mu_{\=  x }, from a sample size of 36 is  mathematically represented as

        \mu_{\= x } =  \mu

=>     \mu_{\= x } =  100

According to the Central Limit Theorem the test stated in the question is  approximately normally distributed if the sample size is sufficiently large(n  >  30 ) so given that the sample size is  large  n =  36

Then the test is normally distributed and hence the standard deviation is 15

Generally the standard error of mean is mathematically represented as

     \sigma_{\= x } =  \frac{ \sigma }{\sqrt{n} }

=>  \sigma_{\= x } =  \frac{15}{\sqrt{36} }

=>  \sigma_{\= x } = 2.5

Generally  the approximate probability of observing a sample mean of 105.1 or more is mathematically represented as

        P( \=  X   \ge 105.1 ) =1 -  P(\= X  <  105.1) = 1-  P(\frac{\= X -  \mu }{\sigma_{\= x }}

=>    P( \=  X   \ge 105.1 ) =1 -  P(\= X  <  105.1) = 1-  P(Z

From the z-table (reference calculator dot net )

             P(Z

So

  P( \=  X   \ge 105.1 )= 1 -  P(\= X  <  105.1) = 1-  0.97932

 P( \=  X   \ge 105.1 ) =0.02    

4 0
4 years ago
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