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Ulleksa [173]
3 years ago
10

Please answer correctly.

Mathematics
1 answer:
Murljashka [212]3 years ago
3 0

In order to find the amount left after both sisters ate the cereal, we have to add the amount of cereal the two sisters ate.

Katrina ate 1 3/4 and her sister ate 7/8.

(1 3/4 + 7/8)

(you put a parentheses around it so that you add the two first before subtracting it from the original amount)

Then, we would subtract it from the original amount: 12 1/2.

-> The equation would be: 12 1/2 - (1 3/4 - 7/8).

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Three times a number, added to 9 is 33 find the number
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3 x 8 = 24 
24 + 9 = 33

"the number" = 8
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A is an m×n matrix.Check the true statements below:A. The kernel of a linear transformation is a vector space.B. If the equation
Bess [88]

Answer:

Results are (1) True. (2) False. (3) False. (4) True. (5) True. (6) True.

Step-by-step explanation:

Given A is an m\times n matrix.  Let T :U\to V  be the corresponding linear transformationover the field F and \theta be identity vector in V. Now if x\in Ker( T)\implies T(x)=\theta.

(1) The kernel of a linear transformation is a vector space : True.

Let x,y\in Ker( T), then,

T(x+y)=T(x)+T(y)=\theta+\theta=\theta\impies x+y\in Ker( T)

hence the kernel is closed under addition.

Let \lambda\in F, x\in Ker( T), then

T(\lambda x)=\lambda T(x)=\lambda\times \theta=\theta

\lambda x\in Ker(T) and thus Ket(T) is closed under multiplication

Finally, fore all vectors u\in U,

T(\theta)=T(\theta+(-\theta))=T(\theta)+T(-\theta)=T(\theta)-T(\theta)=\theta

\implies \theta\in Ker(T)

Thus Ker(T) is a subspace.

(2) If the equation Ax=b is consistent, then Col(A) is \mathbb R^m : False

if the equation Ax=b is consistent, then Col(A) must be consistent for all b.

(3) The null space of an mxn matrix is in \mathbb R^m

: False

The null space that is dimension of solution space of an m x n matrix is always in \mathbb R^n.

(4) The column space of A is the range of the mapping x\to Ax

: True.

(5) Col(A) is the set of all vectors that can be written as Ax for some x. : True.

Here Ax will give a linear combination of column of A as a weights of x.

(6) The null space of A is the solution set of the equation Ax=0.

: True

5 0
3 years ago
Resuelve las siguientes ecuaciones
N76 [4]

Answer:


Step-by-step explanation:


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3 years ago
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