A function with a positive constant other than 1 raised to a variable exponent is known as an exponential function. As a function is evaluated, it is solved at a given input value. Where the growth rate and initial value are known, an exponential formula can be used.
Sorry I dont know much about them but I hope this helps you!!
Answer:
310
Step-by-step explanation:
Use the Order of Operations method. (P.E.M.D.A.S.)
Our expression: 3+2⋅4+62⋅5−1
<u>Multiply 62 and 5, and 2 and 4:</u>
3+8+310-1
<u>Add and Subtract from left to right:</u>
11+310-1
311-1
310
1a:
580 - (580 × .1) - 20
580 - (58) - 20
522 - 20
502
1b:
990 - (990 × .25) - 20
990 - (247.5) - 20
742.5 - 20
722.5
I'm not sure how to solve #2.
Answer:
1.45
2.61
3.33
4.108
5.98
6.82
7.52
8.142
9.36
10.64
Step-by-step explanation:
Use rule that a straight line is 180 and a right angle is 90
