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DiKsa [7]
3 years ago
11

Tell me how you solved thanks

Mathematics
1 answer:
Allushta [10]3 years ago
4 0
A. Similar triangles have equal angles even though they're not the same size that was similar means So then

X^2-5x=4x+36
X^2-5x-4x-36=0
X^2-9x-36=0
(X-12)(x(+3)
X=12. X=3

Angle C and angle F are equal
So 4(12)-5=43
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If
swat32

Answer:

55a=

step-by-step explanation:

5 0
2 years ago
One-fourth of the sum of 6 and 2 times c exceeds 3.
Sergeeva-Olga [200]
1/4(6 + 2c) > 3
0.25 (6+ 2c) > 3
1.5 + 0.5c > 3
0.5c > 1.5
c > 3

Or multiply both sides by 4 to get rid of the 1/4,
6 + 2c > 12
2c > 6
c >3
4 0
3 years ago
Translate the verbal expression "Five less than the product of X and three" into an algebraic expression
Illusion [34]

Answer:

x+3-5 i think

Step-by-step explanation:

"and" means add so x+3 and subtract 5

6 0
3 years ago
59-(2c+3)=4(c+7)+c.
alisha [4.7K]

Step-by-step explanation:

{:}\leadsto\sf 59-(2c+3)=4 (c+7)+c

{:}\leadsto\sf 59-2c-3=4c+28+c

{:}\leadsto\sf 56-2c=5c+28

{:}\leadsto\sf 5c+28=56-2c

{:}\leadsto\sf 5c+2c=56-28

{:}\leadsto\sf 7c=28

{:}\leadsto\sf c={\dfrac {28}{7}}

{:}\leadsto\sf c=4

4 0
3 years ago
Read 2 more answers
Which expression is equivalent to StartRoot 120 x EndRoot?.
Irina-Kira [14]

Here for 120, the expression for the start root and end root is given  

\sqrt{120} =2\sqrt{30}

<h3>What will be the expression for start root and enroot of 120?</h3>

Here we need to find \sqrt{120}

By simplifying the given expression, we get:

120=2\times2\times2\times3\times5

120=(2^{2} )\times3\times5

by taking square roots on both sides we get

\sqrt{120} =2\sqrt{30}

Thus for 120, the expression for the start root and end root is given  \sqrt{120} =2\sqrt{30}

To know more about the Square roots follow

brainly.com/question/124481

5 0
2 years ago
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