Answer:
![\huge \boxed{f(-2)=6}](https://tex.z-dn.net/?f=%5Chuge%20%5Cboxed%7Bf%28-2%29%3D6%7D)
Step-by-step explanation:
![\sf f(x)=-1x+4](https://tex.z-dn.net/?f=%5Csf%20f%28x%29%3D-1x%2B4)
Switching x variable with -2.
![\sf f(-2)=-1(-2)+4](https://tex.z-dn.net/?f=%5Csf%20f%28-2%29%3D-1%28-2%29%2B4)
Evaluating.
![\sf f(-2)=2+4](https://tex.z-dn.net/?f=%5Csf%20f%28-2%29%3D2%2B4)
![\sf f(-2)=6](https://tex.z-dn.net/?f=%5Csf%20f%28-2%29%3D6)
Answer:
4(x+2) / 5(x-1)
Step-by-step explanation:
We have given two expressions.
2x / x-1 expression I
5x / 2x+4 expression II
we have to find the quotient of expression I and expression II.
(2x / x-1 ) ÷ (5x / 2x+4)
Applying following rule:
a ÷ b = a× 1/b
(2x/x-1)×( 2x+4 / 5x)
(2x)(2x+4) / (x-1)(5x)
(2)(2)(x+2) / (x-1)(5)
4(x+2) / 5(x-1) which is the answer of given question.
The mean to this question is 87.875
Answer:
Step-by-step explanation:
If <A and <B are vertical Angeles it implies they are equal
: 5x + 2 = 6x - 12
5x - 6x = -12 - 2
-x = - 14
x = 14°
Answer:
The decision rule is
Fail to reject the null hypothesis
The conclusion is
There is no sufficient evidence to conclude that the average is a different number for college students
Step-by-step explanation:
From the question we are told that
The sample size is n = 50
The population mean is
The sample mean is
The standard deviation is
The level of significance is ![\alpha = 0.10](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%200.10)
The null hypothesis is ![H_o : \mu = 4](https://tex.z-dn.net/?f=H_o%20%20%3A%20%20%5Cmu%20%3D%20%204)
The alternative hypothesis is ![H_a : \mu \ne 4](https://tex.z-dn.net/?f=H_a%20%3A%20%20%5Cmu%20%5Cne%204)
Generally the test statistics is mathematically represented as
![z = \frac{ \= x - \mu }{ \frac{ \sigma }{ \sqrt{n}} }](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B%20%5C%3D%20x%20%20-%20%20%5Cmu%20%7D%7B%20%5Cfrac%7B%20%5Csigma%20%7D%7B%20%5Csqrt%7Bn%7D%7D%20%7D)
=> ![z = \frac{ 3.79 - 4 }{ \frac{1.2}{ \sqrt{50}} }](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B%203.79%20%20%20-%20%204%20%7D%7B%20%5Cfrac%7B1.2%7D%7B%20%5Csqrt%7B50%7D%7D%20%7D)
=> ![z = -1.237](https://tex.z-dn.net/?f=z%20%3D%20-1.237)
From the z table the area under the normal curve to the left corresponding to -1.237 is
![P(Z < -1.237) = 0.10804](https://tex.z-dn.net/?f=P%28Z%20%3C%20%20%20-1.237%29%20%3D%200.10804)
Generally the p-value is mathematically represented as
![p-value = P(Z < -1.237) = 2 * 0.10804](https://tex.z-dn.net/?f=p-value%20%20%3D%20%20P%28Z%20%3C%20%20%20-1.237%29%20%3D%202%20%2A%200.10804)
=> ![p-value = 0.21608](https://tex.z-dn.net/?f=p-value%20%20%3D%20%200.21608)
Generally from the values obtained we see that
![p-value > \alpha](https://tex.z-dn.net/?f=p-value%20%3E%20%20%5Calpha)
Hence
The decision rule is
Fail to reject the null hypothesis
The conclusion is
There is no sufficient evidence to conclude that the average is a different number for college students