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suter [353]
3 years ago
7

A mutation of the proteolytic enzyme Trypsin (described in Section 6.1) results in a stable covalent bond between one of the cat

alytic amino acids of the protease and its protein substrate. Which of the following are probably true?
a. The enzyme would become inactive.
b. The enzyme and substrate would be stuck together.
c. The delta-G of the proteolysis reaction would change.
d. The rate of the catalyzed reaction would increase.
Biology
1 answer:
jolli1 [7]3 years ago
5 0

Answer:

b. The enzyme and substrate would be stuck together.

Explanation:

Enzymes are proteins whose active site binds to specific chemical reactants (i.e., substrates), thereby forming a complex that is similar to the interaction between a lock and its key. This active complex lowers the energy of the reaction and promotes a conformational change in the substrate to break down it into multiple products. When the enzyme contains mutations in its active site, the ability to bind the substrate is altered. In this case, the enzymatic reaction can't occur because the interaction enzyme-substrate doesn't produce an active complex.

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Answer: In the middle intertidal, barnacles, mussels and seaweeds all compete for space – a precious limited resource. Mussels are generally the dominant competitor on rocky shores and without the presence of predatory seastars would outcompete other taxa and occupy all available space.

Explanation:

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In mouse, genes X, Y and Z are on chromosome 2. The map of genes X, Y and Z is:
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Answer:

36 individuals xxyyzz

Explanation:

<u>Available data:</u>

  • X-Y = 20MU
  • Y-Z = 30MU
  • Cross: XXYYZZ   x    xyyzz
  • F1= XxYyZz
  • I = 40%
  • 2nd Cross: XxYyZz  x  xxYyzz
  • F2 = 1000 individuals

We need to know how many individuals from the F2 are going to be xxyyzz

xxyyzz genotype is the result of a double recombinant event.

First, we need to analyze the given information:

<em><u>→ Distances between genes</u></em>

The genetic distance result from multiplying the recombination frequency of each region by 100 and expressing it in map units (MU). So, if we have the genetic distance we can divide it by 100 and get the recombination frequency:

Let us say that region I is the distance between X and Y. And region II is the distance between Y and Z.

<em>GD = genetic distance</em>

<em>RF = Recombination frequency</em>

  • GD (X-Y) = RF x 100

20MU = RF x 100

20MU/100 = RF

0.2 = RF (Region I)

  • GD (Y-Z) = RF x 100

30MU = RF x 100

30MU/100 = RF

0.3 = RF (Region II)      

Now we have the recombination frequency of Region I and Region II.

<u><em>→ Interference</em></u>    

Knowing the interference value will let us know the value of the coefficient of coincidence, which will also lead us to the number of individuals xxyyzz.

I = 40%

I = 1 - CC   ⇒ <em>CC = coefficient of coincidence</em>

Clearing this equation gives us the value of CC

CC = 1 - I

CC = 1 - 40% = 1 - 0.4

CC = 0.6

To calculate the coefficient of coincidence, CC, we can also use the next formula:

CC = observed double recombinant frequency/expected double recombinant frequency

Now, we are interested in knowing the value of the <em>observed double recombinant frequency.</em>

<em>Note:</em>  

  • observed double recombinant frequency = total number of observed double recombinant individuals/total number of individuals
  • expected double recombinant frequency = recombination frequency in region I x recombination frequency in region II.

So, to get the value of the observed double recombinant frequency, first, we need to get the value of the expected double recombinant frequency. And we can do it because we already have the recombination frequencies in both regions.

expected double recombinant frequency = recombination frequency in region I x recombination frequency in region II

- Recombination Frequency - RI = 0.2

- Recombination Frequency  - RII = 0.3

expected double recombinant frequency = 0.2 x 0.3

expected double recombinant frequency = 0.06 = EDRF

Now that we know the value of the CC and the expected DRF, we can get the observed double recombinant frequency.

CC = observed double recombinant frequency/expected double recombinant frequency

- CC = 0.6

- EDRF = 0.06

CC x expected double recombinant frequency = observed double recombinant frequency

0.6 x 0.06 = observed double recombinant frequency

0.036 = observed double recombinant frequency = ODRF

Finally, as this is a frequency, we need to multiply it by the total number of individuals in the F2 to get the number of observed double recombinant individuals.

- ODRF = 0.036

- N = 1000

Double recombinant individuals = 0.036 x 1000 = 36 individuals xxyyzz.

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