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Molodets [167]
4 years ago
9

Set up a revenue function, R(n), that can be used to solve the problem, then solve the problem. A business sells n exploding cig

ars, n ≤ 25, at a price of (25 - 0.2n) dollars per cigar. How many exploding cigars must be sold to have a revenue of $120?
Mathematics
1 answer:
alisha [4.7K]4 years ago
5 0

Answer:

• R(n) = n·(25 -0.2n)

• n = 5

Step-by-step explanation:

Revenue is the product of selling price and the number sold. If n cigars are sold at a price of (25-0.2n), then the revenue generated is ...

R(n) = n(25 -0.2n)

__

We want the value of this to be 120, so we want the solution to ...

120 = n(25 -0.2n)

0.2n^2 -25n +120 = 0

n^2 -125n +600 = 0

(n-5)(n-120) = 0

n = 5 . . . . . . . any value above 25 is extraneous

The revenue function is R(n) = n(25-0.2n); 5 cigars must be sold to have a revenue of $120.

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Answer:

you would figure out the time in either pst or est and find out the time

Step-by-step explanation:

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4 years ago
The record for the most rolls of wrapping paper sold for the school fundraiser is 593. Let w be the number of rolls of wrapping
astra-53 [7]

Answer:

w ≤ 593

Step-by-step explanation:

Missing option;

w ≥ 593

w > 593

w ≤ 593

593 < w

Explanation:

w ≥ 593    No

Number of wrapping paper sold never be more than 593.

w > 593    no

Number of wrapping paper sold never be more than 593.

w ≤ 593  yes

Number of wrapping paper sold will be equal or less than 593.

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3 years ago
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Step-by-step explanation:

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So, he worked 5.5h and he earns $10.50 an hour.

($10.50)(5.5h)=$57.75

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Step-by-step explanation:

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