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sattari [20]
3 years ago
15

The coordinates of the vertices of triangle ABC are A (1,-1),B (1,4), and C (8,4). what is the length in units of the line segme

nt that connects vertex A and vertex B
Mathematics
1 answer:
Vinil7 [7]3 years ago
4 0

The length of the line segment that connects vertex A and vertex B is 5 units

Step-by-step explanation:

Let us revise some facts about the horizontal and vertical segments

  • The segment is horizontal if the y-coordinates of all points on the segment are equal
  • The length of the horizontal segment whose endpoints are (x_{1},y) and (x_{2},y) is x_{2}-x_{1}
  • The segment is vertical if the x-coordinates of all points on the segment are equal
  • The length of the vertical segment whose endpoints are (x,y_{1}) and (x,y_{2}) is y_{2}-y_{1}

In Δ ABC

∵ A = (1 , -1)

∵ B = (1 , 4)

∵ C = (8 , 4)

∵ The x-coordinate of point A = 1

∵ The x-coordinate of point B = 1

∴ The x-coordinates of points A and B are equal

- The x-coordinates of A and B are equal, then the line AB is a

  vertical segment

∴ The length of AB is the difference between the y-coordinates

   of points A and B

∵ The y-coordinate of point A = -1

∵ The y-coordinate ob point B = 4

∴ The length of AB = 4 - (-1)

∴ The length of AB = 4 + 1

∴ The length of AB = 5 units

The length of the line segment that connects vertex A and vertex B is 5 units

Learn more:

You can learn more about the length of the segments in brainly.com/question/6564657

#LearnwithBrainly

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Answer:

The 99% confidence interval is   165.776  <  \mu <  180.224  

Step-by-step explanation:

From the question we are told that

     The sample size is  n  = 100

     The sample mean is  \=  x  =  173 \  days

      The population standard deviation is  \sigma =  28 \ days  

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

      E = 2.58  *  \frac{28 }{\sqrt{100} }

=>    E = 7.224

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=>     173 -7.224  <  \mu < 173 + 7.224    

=>     165.776  <  \mu < 180.224  

     

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