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sattari [20]
3 years ago
15

The coordinates of the vertices of triangle ABC are A (1,-1),B (1,4), and C (8,4). what is the length in units of the line segme

nt that connects vertex A and vertex B
Mathematics
1 answer:
Vinil7 [7]3 years ago
4 0

The length of the line segment that connects vertex A and vertex B is 5 units

Step-by-step explanation:

Let us revise some facts about the horizontal and vertical segments

  • The segment is horizontal if the y-coordinates of all points on the segment are equal
  • The length of the horizontal segment whose endpoints are (x_{1},y) and (x_{2},y) is x_{2}-x_{1}
  • The segment is vertical if the x-coordinates of all points on the segment are equal
  • The length of the vertical segment whose endpoints are (x,y_{1}) and (x,y_{2}) is y_{2}-y_{1}

In Δ ABC

∵ A = (1 , -1)

∵ B = (1 , 4)

∵ C = (8 , 4)

∵ The x-coordinate of point A = 1

∵ The x-coordinate of point B = 1

∴ The x-coordinates of points A and B are equal

- The x-coordinates of A and B are equal, then the line AB is a

  vertical segment

∴ The length of AB is the difference between the y-coordinates

   of points A and B

∵ The y-coordinate of point A = -1

∵ The y-coordinate ob point B = 4

∴ The length of AB = 4 - (-1)

∴ The length of AB = 4 + 1

∴ The length of AB = 5 units

The length of the line segment that connects vertex A and vertex B is 5 units

Learn more:

You can learn more about the length of the segments in brainly.com/question/6564657

#LearnwithBrainly

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Answer:

A. add 81; (x-9)^2

Step-by-step explanation:

The perfect square formula

(a-b)^2=a^2-2ab+b^2

Rewrite expression x^2-18x as follows:

x^2-2\cdot 9\cdot x

So, to form a perfect square, +9^2 is missed.

When we add 9^2=81, we will get

x^2-2\cdot 9\cdot x+9^2=(x-9)^2

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Which ordered pair is a solution to the system of inequalities?
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Two students solved the same multi-step equation. Which student is correct? Explain the error. Student A Student B 2x - 4(3x + 6
Gnom [1K]

Answer:

Student B is correct

Student A failed to distribute -4 and -6 when opening the brackets in the first step

Step-by-step explanation:

The solution Student A gave was:

2x - 4(3x + 6) = -6(2x + 1) - 4

2x - 12x + 6 = -12x + 1 - 4

-10x + 6 = -12x - 3

2x = -9

x = -4 _1 2 ( -4 1/2)

The solution Student B gave was:

2x - 4(3x + 6) = -6(2x + 1) - 4

2x - 12x - 24 = -12x - 6 - 4

-10x - 24 = -12x - 10

2x = 14

x = 7

Student B is correct.

Explanation of the error:

Student A failed to distribute -4 and -6 when opening the brackets in the first step.

That is,

2x - 4(3x + 6) = -6(2x + 1) - 4

To open this bracket, we will distribute, -4 and -6 so that we get

2x (-4 × 3x) + (-4 × +6) = (-6×2x) + (-6 × +1) - 4

Then we will get

2x -12x -24 = -12x -6 -4

Adding the like terms

-10x - 24 = -12x - 10

Collecting like terms

-10x + 12x = -10 + 24

∴ 2x = 14

x = 14 / 2

Hence,

x = 7

8 0
3 years ago
Can somebody please help me​
Westkost [7]
-5 = n + 14
So, n = -19
4 0
3 years ago
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