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3 years ago

Use the coordinates of the plotted points to complete the calculation below. Pay attention to negative signs.

Mathematics

2 answers:

MArishka [77]3 years ago

7 0

Answer:

3
1
-3
1
-3

Step-by-step explanation:

The change in y is the difference in y-coordinates between the lower right point and the upper left point. Similarly, the change in x is the difference in the x-coordinates of those points.

$\text{Slope}=\dfrac{\text{change in y}}{\text{change in x}}=\dfrac{\boxed{3}-6}{2-\boxed{1}}\\\\=\dfrac{\boxed{-3}}{\boxed{1}}\\\\\\=\boxed{-3}$

Igoryamba3 years ago

3 0

answer 3-6 and 2-1 the bottom box is -3 over 1 final answer -3 hope this helped you

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Julia is five years older than her sister Babs, and their ages add up to 31. How old is Babs?

Tresset [83]

Julia is X+5

x+x+5=31

Now we just solve the equation

2x=31-5
x=26/2
x=13 years old (Babs' age)

and we know that julia is 5 years older this gives us the conclusion that.

13+18=31

4 0

3 years ago

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What number must be added to the expression below to complete the square?

stiv31 [10]

D. 1/4

Explanation:

a perfect square is written in the form

$(x+a)^2 = x^2 + 2ax +a^2$ (1)

In our problem, we have this perfect square:

$x^2 - x + C$ (2)

with C being unknown. However, by comparing (1) and (2), we know that

$2a=-1$

So, we find

$a=-\frac{1}{2}$

and therefore, the missing term must be

$a^2 = \frac{1}{4}$

so the complete square is

$x^2 -x +\frac{1}{4}$

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2 years ago

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Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :