Answer:
lw +
× π ×
⇒ Answer D is correct
Step-by-step explanation:
First, let us find the area of the semi-circle.
Area =
× π × r²
<u>Given that,</u>
diameter of the semi-circle is ⇒ <em>l</em>
∴ radius ⇒ <em>l / 2</em>
<u>Let us find it now.</u>
Area =
× π × r²
Area =
× π × 
<u> </u>
Secondly, let us find the area of the rectangle.
Area = length × width
<u>Given that,</u>
length ⇒ <em>l</em>
width ⇒ w
<u>Let us find it now.</u>
Area = length × width
Area = l ×w
Area = lw
<u> </u>
And now let us <u>find the total area.</u>
Total area = Area of the rectangle + Area of the semi - circle
Tota area = lw +
× π × 
We can factor <span>4x^2-25 into (2x +5) * (2x -5) and
dividing by (2x -5)
yields (2x +5)
That neatened up pretty nicely.</span>
$38.05 or more because you need a minimum of $38.10
Check the picture below.
is it even? well, even functions use the y-axis as a mirror, so a pre-image on the right-side, will be a mirror of the image on the left-side, but in this case it isn't so, if you put a mirror right on the y-axis, the left-side will look a bit different.
does it have a zero at x = 0? well, just look at the graph, is the line touching the x-axis at 0? nope.
does it have an asymptote at 0? well, surely you can see it right there.