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Tju [1.3M]
3 years ago
8

Use the coordinates of the plotted points to complete the calculation below. Pay attention to negative signs.

Mathematics
2 answers:
MArishka [77]3 years ago
7 0

Answer:

  • 3
  • 1
  • -3
  • 1
  • -3

Step-by-step explanation:

The <em>change in y</em> is the difference in y-coordinates between the lower right point and the upper left point. Similarly, the <em>change in x</em> is the difference in the x-coordinates of those points.

  \text{Slope}=\dfrac{\text{change in y}}{\text{change in x}}=\dfrac{\boxed{3}-6}{2-\boxed{1}}\\\\=\dfrac{\boxed{-3}}{\boxed{1}}\\\\\\=\boxed{-3}

Igoryamba3 years ago
3 0

answer 3-6 and 2-1 the bottom box is -3 over 1 final answer -3 hope this helped you

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Julia is five years older than her sister Babs, and their ages add up to 31. How old is Babs?
Tresset [83]
<span>Julia is X+5

</span><span>x+x+5=31
</span>
Now we just solve the equation 

2x=31-5
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and we know that julia is 5 years older this gives us the conclusion that. 

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4 0
3 years ago
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stiv31 [10]

D. 1/4

Explanation:

a perfect square is written in the form

(x+a)^2 = x^2 + 2ax +a^2 (1)

In our problem, we have this perfect square:

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2 years ago
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Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

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t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

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