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slamgirl [31]
3 years ago
9

A test has multiple choice questions with 5 choices for each answer, only one answer is correct for each question. Suppose a stu

dent guesses the answer to each question. Assuming the guesses are independent, find the probability that the student will not guess correctly on any one question.
Mathematics
1 answer:
Brrunno [24]3 years ago
6 0

Answer:

The probability that the student will not guess correctly on any one question is 4/5

Step-by-step explanation:

The question posed is an application of the binomial probability distribution.

We have been informed that the test has multiple choice questions with 5 choices for each answer that only one answer is correct for each question.

If the student guesses the answer to each question, then the probability that the student will guess correctly on any one question is 1/5.

Therefore, the probability that the student will not guess correctly on any one question is;

1 - 1/5 = 4/5

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aivan3 [116]
I'm assuming that you meant: 
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Remember! Inputs are always x values (unless stated otherwise). Meaning the problem says: 
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y = 7(4)² + 3 

The square only applies to the 4. The 7 is not going to be squared! (To be exact it only applies to whatever the value of x is. 

4² = 4·4 = 16

Remember: 
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Follow PEMDAS from left to right (or in the case above from top to bottom).

7·16 + 3 = ? 

16·7 = 10·7 + 6·7 = 70 + 42 = 112
(All I did to multiply was break it up into parts. If it confuses you don't worry about it, and just multiply it out like normal or use a calculator if you are allowed to)

112 + 3 = ? 

Our output is: 
115!
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