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slamgirl [31]
3 years ago
9

A test has multiple choice questions with 5 choices for each answer, only one answer is correct for each question. Suppose a stu

dent guesses the answer to each question. Assuming the guesses are independent, find the probability that the student will not guess correctly on any one question.
Mathematics
1 answer:
Brrunno [24]3 years ago
6 0

Answer:

The probability that the student will not guess correctly on any one question is 4/5

Step-by-step explanation:

The question posed is an application of the binomial probability distribution.

We have been informed that the test has multiple choice questions with 5 choices for each answer that only one answer is correct for each question.

If the student guesses the answer to each question, then the probability that the student will guess correctly on any one question is 1/5.

Therefore, the probability that the student will not guess correctly on any one question is;

1 - 1/5 = 4/5

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How can -6.75 + (10.25) be expressed as the sum of its integer and decimal parts
ArbitrLikvidat [17]

Answer:

 -6.75 + (10.25)    =  ( (-6)  + (10))  + ( (-0.75) + (0.25))

Here, the integer part  =     ( (-6)  + (10))

Decimal part =   ( (-0.75) + (0.25))

Step-by-step explanation:

Here, the given expression is:    -6.75 + (10.25)

Now, -6.75  = (-6)  +  (-0.75)

Also, (10.25)  = (10)  + (0.25)

So, the expression can be written as

 -6.75 + (10.25)  =  (-6)  +  (-0.75) +  (10)  + (0.25)

                           = ( (-6)  + (10))  + ( (-0.75) + (0.25))

or,   -6.75 + (10.25)    =  ( (-6)  + (10))  + ( (-0.75) + (0.25))

Where the integer part is    ( (-6)  + (10))

and the decimal part is  ( (-0.75) + (0.25))

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3 years ago
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wolverine [178]
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What number is between 27 and 45
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It could be 28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43, or 44.
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Step-by-step explanation:

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nevsk [136]

#Personal computer:-

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Percent

\\ \bull\sf\dashrightarrow \dfrac{480}{1500}\times 100

\\ \bull\sf\dashrightarrow 32\%

#Pacemaker:-

\\ \bull\sf\dashrightarrow 0.26(1500)

\\ \bull\sf\dashrightarrow 390

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\\ \bull\sf\dashrightarrow 0.18(1500)

\\ \bull\sf\dashrightarrow 270

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\\ \bull\sf\dashrightarrow \dfrac{150}{1500}\times 100

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\\ \bull\sf\dashrightarrow 0.14(1500)

\\ \bull\sf\dashrightarrow 225

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