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Paladinen [302]
2 years ago
9

Find the equation of the line that is parallel to y = 2x - 7 and contains the point (-3,6)

Mathematics
1 answer:
marissa [1.9K]2 years ago
6 0

1) The first step is to Know the condition for two lines be parallel is that have the same slope, and this form the slope given is 2, therefore the new function has its slope too

2)  with the slope and the two points givens, you can find the equation

Y-Y1 = m( X-X1) ,   Y-6 = 2[(X-(-3)]  ⇒Y-6 = 2X+6 ⇒Y = 2X+12, AND THIS IS THE EQUATION PARALLEL TO THE LINE Y = 2X-7

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2 years ago
Write a similarity statement comparing the three triangles in the diagram<br> P R S Q
REY [17]

Answer:

The answer is ΔJMK ≈ ΔMLK ≈ ΔJLM ⇒ answer (A)

Step-by-step explanation:

* Lets start with the equal angles i the three triangles

- In ΔJMK

∵ m∠JKM = 90°

∴ m∠KJM + m∠KMJ = 90 ⇒ (1)

- IN ΔMLK

∵ m∠MKL = 90°

∴ m∠KML + m∠KLM = 90° ⇒ (2)

∵ m∠KMJ + m∠KML = 90° ⇒ (3)

- From (1) , (2) , (3)

∴ m∠KJM = m∠KML

∴ m∠KMJ = m∠KLM

* Now lets check the condition of similarity in the 3 triangles

- At first ΔJMK and ΔMLK

- In triangles JMK , MLK

∵ m∠KJM = m∠KML

∵ m∠KMJ = m∠KLM

∵ m∠JKM = m∠MKL

∴ ΔJMK ≈ ΔMLK ⇒ (4)

- At second ΔJMK and ΔJLM

∵ m∠KJM = m∠MJL

∵ m∠KMJ = m∠MLJ

∵ m∠JKM = m∠JML

∴ ΔJMK ≈ ΔJLM ⇒ (5)

* If two triangles are similar to one triangle, then they are

similar to each other

- From (4) and(5)

∴ ΔJMK ≈ ΔMLK ≈ ΔJLM

6 0
2 years ago
In order to write the equation of the line passing through the point (-2, 2) that is parallel to the line y = 2x + 3 , the next
OlgaM077 [116]

Answer:

Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. Thus, the equation of the line is y = ½x + 6.

6 0
2 years ago
Read 2 more answers
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