Best definition combining like terms

1 answer:

7 0

<span>A letter that holds the place for some unknown value in mathematics VARIABLE A process where you must look for terms that have identical variable parts and then combine their coefficients. COMBINING LIKE TERMS</span>

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A number divided by 6 is 18

defon

108.

Exp: multiply 6*18 to get the answer because we are working backwards

7 0

3 years ago

Read 2 more answers

Which of the following describes graphing y ≥ |x| + 4?

kolbaska11 [484]

Answer:

Translate $y=\left|x\right|$ up $4$ units and shade inside the V

Step-by-step explanation:

we know that

The function $y=\left|x\right|$ has the vertex at point $(0,0)$

The function $y=\left|x\right|+4$ has the vertex at point $(0,4)$

the rule of the translation is

$(x,y)------> (x,y+4)$

That means

The translation is $4$ units up

The solution of the inequality $y\geq\left|x\right|+4$

is the shaded area inside the V

see the attached figure to better understand the problem

therefore

the answer is

Translate $y=\left|x\right|$ up $4$ units and shade inside the V

5 0

3 years ago

Read 2 more answers

You decide to put $5000 in a savings account to save $6000 down payment on a new car. If the account has an interest rate of 7%

bezimeni [28]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill&\$6000\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years \end{cases}$

$\bf 6000=5000\left(1+\frac{0.07}{12}\right)^{12\cdot t}\implies \cfrac{6000}{5000}\approx (1.0058)^{12t}\implies \cfrac{6}{5}\approx(1.0058)^{12t} \\\\\\ \log\left( \cfrac{6}{5} \right)\approx \log[(1.0058)^{12t}]\implies \log\left( \cfrac{6}{5} \right)\approx 12t\log(1.0058) \\\\\\ \cfrac{\log\left( \frac{6}{5} \right)}{12\log(1.0058)}\approx t\implies 2.63\approx t\impliedby \textit{about 2 years, 7 months and 16 days}$