Unit 22. Practice test

Help needed fast!!!

kicyunya [14]

Answer:

The answer is A

Step-by-step explanation:

It has to exceed not be same or equal to

6 0

3 years ago

Read 2 more answers

A horse takes 3 steps to walk the same distance for which a goat takes 4 steps. Suppose 1 step of the dog covers 1/2 of a metre.

almond37 [142]

Answer:

The goat would cover 9 meters in taking 24 steps.

Step-by-step explanation:

There is a mistake in the question so the correct question is below:

A horse takes 3 steps to walk the same distance for which a goat takes 4 steps. Suppose 1 step of the horse covers 1/2 of a metre. How many metres would the goat cover in taking 24 steps?

Now, to find the meters goat cover in taking 24 steps.

As 1 step of horse covers = $\frac{1}{2} \ meter.$

So, 3 step of horse covers = $\frac{1}{2} \times 3$ $=\frac{3}{2} =1.5\ meters.$

Thus, 3 steps of horse covers = 1.5 meters.

As given, the horse takes 3 steps to walk the same distance for which a goat takes 4 steps.

So, the distance covers by goat in 4 steps = 1.5 meters.

Now, to get the meters goat cover in taking 24 steps by using unitary method:

If, the distance cover by the goat in 4 steps = 1.5 meters

So, the distance cover by the goat in 1 step = $\frac{1.5}{4}$

Thus, the distance cover by the goat in 24 steps = $\frac{1.5}{4}\times 24$

= $\frac{36}{3}$

= $9\ meters.$

Therefore, the goat would cover 9 meters in taking 24 steps.

8 0

3 years ago

Help me with 16,17,18,and 19 please simpl

mixas84 [53]

Answer:

Ques 16)

We have to simplify the expression:

$\dfrac{t^2}{t^2+3t-18}-(\dfrac{5t}{t^2+3t-18}-\dfrac{t-3}{t^2+3t-18})\\ \\=\dfrac{t^2}{t^2+3t-18}-(\dfrac{4t+3}{t^2+3t-18})\\ \\=\dfrac{t^2-4t-3}{t^2+3t+18}$

Ques 17)

$\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{2w^2-9w+4}{(2w^2+9w-5)(w^2-w-12)}\\ \\=\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{(2w-1)(w-4)}{(2w-1)(w+5)(w+3)(w-4)}\\\\=\dfrac{3w^2+7w-7}{(w+3)(w+5)}+\dfrac{1}{(w+3)(w+5)}\\\\=\dfrac{3w^2+7w-7+1}{(w+3)(w+5)}\\\\=\dfrac{(3w-2)(w+3)}{(w+5)(w+3)}\\\\=\dfrac{3w-2}{w+5}$

Ques 18)

Let the blank space be denoted by the quantity 'x'.

$\dfrac{x}{12a^2+8a}+\dfrac{15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\ \\\dfrac{x+15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a(3a+2)}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a}=7a\\\\x+15a^2=28a^2\\\\x=28a^2-15a^2\\\\x=13a^2$

Ques 19)

Let the missing quantity be denoted by 'x'.

$\dfrac{p^2+7p+2}{p^2+5p-14}-\dfrac{x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\ \\\dfrac{p^2+7p+2-x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\\\\dfrac{p^2+7p+2-x}{(p-2)(p+7)}=\dfrac{p-1}{p-2}\\\\p^2+7p+2-x=(p-1)(p+7)\\\\p^2+7p+2-x=p^2+6p-7\\\\x=p+9$