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olchik [2.2K]
4 years ago
15

Carey is trying to decide between two guitars. The first had an original price of $160, but is on sale for $100. The second had

an original price of $250, but is on sale for $150. Which guitar has a greater percent change in price?
Mathematics
2 answers:
dexar [7]4 years ago
8 0
The second guitar is the answer because it has a lower amount than the first but not by alot
Naddik [55]4 years ago
5 0
The original prices of the guitars are 100%. Example: for the $160 guitar, $160 would be 100% of the price. The new price is $100. The guitar went down $160-$100=$60. 60/160 = 0.375. Convert that into a percentage. 0.375 = 37.5%. Guitar number one has decreased by 37.5%. 
Guitar number 2: $250 = 100%. It went down $250-$150=$100. 100/250 = 0.40. Convert to percentage. 0.40 = 40%. 
Guitar 1 had a decrease of 37.5% in price
Guitar 2 had a decrease of 40% in price.
Hope this helps!
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mrs_skeptik [129]

For the points in the parabola, we have:

  • A = (1, 0)
  • B = (3, 0)
  • P = (0, 3)
  • Q = (2, -1).

<h3>How to identify the points on the parabola?</h3>

Here we have the quadratic equation:

y = (x - 1)*(x - 3)

First, we want the coordinates of A and B, which are the two zeros of the parabola.

Because it is already factorized, we know that the zeros are at x = 1 and x = 3, so the coordinates of A and B are:

A = (1, 0)

B = (3, 0).

Then point P is the y-intercept, to get it, we need to evaluate in x = 0.

y = (0 - 1)*(0 - 3) = (-1)*(-3) = 3

Then we have:

P = (0, 3)

Finally, point Q is the vertex. The x-value of the vertex is in the middle between the two zeros, so the vertex is at x = 2.

And the y-value of the vertex is:

y = (2 - 1)*(2 - 3) = 1*(-1) = -1

So we have:

Q = (2, -1).

If you want to learn more about quadratic equations:

brainly.com/question/1214333

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6 0
2 years ago
A particle is moving horizontally along the x-axis. Its position (in ft) is: s(t)=t^3-18t^2+33t+14 where t is in sec.
UNO [17]

Answer:

t=11 sec

Step-by-step explanation:

The position of the particle moving along the x-axis is given by:

s(t) =  {t}^{3}  - 18 {t}^{2}  + 33t + 14

The velocity is given by:

s'(t) = 3 {t}^{2}  - 36{t} + 33

If s'(t)>0 then the particle is moving right.

3 {t}^{2}  - 36{t} + 33 \:  >  \: 0 \\  {t}^{2}  - 12{t} + 11\:  >  \: 0

\implies \: t \:  <  \: 1 \: or \: t \:  >  \: 11

This means that the particle is moving left when

1 \:  <  \: t \:  <  \: 11

The particle changes direction at time t=1 or t=11

8 0
4 years ago
What is the lateral area of the rectangular prism? Assume the prism is resting on its base. A. 135 in2 B. 270 in2 C. 300 in2 D.
Olegator [25]
You have the length of the sides? If not: a and b is the length of the scratch, h is the height <span>This lateral surface area = 2ah+2bh=2h(a+b)</span>
8 0
4 years ago
Triangle ABC with segment BD where point D is between points C and A, BC equals x, BD equals y, CD equals w, DA equals z, and BA
miskamm [114]

Answer:

The correct option is

x equals the square root of w times the sum of w plus z end quantity

Step-by-step explanation:

The parameters given are

ABC = Right triangle, with ∠B = 90° and CA = Hypotenuse = CD + DA

∴ CA = w + z

BA = v

Hence;

x² = (w + z)² - v²

Where:

v² = z² + y²

∴ x² = (w + z)² - (z² + y²)

x² = w² + 2·w·z + z² - z² - y²

x² = w² + 2·w·z - y²

Where:

y² = x² - w²

We have;

x² = w² + 2·w·z - (x² - w²)

x² = w² + 2·w·z - x² + w²

Which gives;

2·x² = 2·w² + 2·w·z

Removing the common factors, we have;

x² = w² + w·z

\therefore x = \sqrt{w^2 + w \times z} =  \sqrt{w  \times(w +  z)}

The correct option is x equals the square root of w times the sum of w plus z end quantity.

8 0
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lakkis [162]

Answer:

7 chairs

Step-by-step explanation:

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and then i solved

and got x=7

7 0
4 years ago
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