For the points in the parabola, we have:
- A = (1, 0)
- B = (3, 0)
- P = (0, 3)
- Q = (2, -1).
<h3>
How to identify the points on the parabola?</h3>
Here we have the quadratic equation:
y = (x - 1)*(x - 3)
First, we want the coordinates of A and B, which are the two zeros of the parabola.
Because it is already factorized, we know that the zeros are at x = 1 and x = 3, so the coordinates of A and B are:
A = (1, 0)
B = (3, 0).
Then point P is the y-intercept, to get it, we need to evaluate in x = 0.
y = (0 - 1)*(0 - 3) = (-1)*(-3) = 3
Then we have:
P = (0, 3)
Finally, point Q is the vertex. The x-value of the vertex is in the middle between the two zeros, so the vertex is at x = 2.
And the y-value of the vertex is:
y = (2 - 1)*(2 - 3) = 1*(-1) = -1
So we have:
Q = (2, -1).
If you want to learn more about quadratic equations:
brainly.com/question/1214333
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Answer:
t=11 sec
Step-by-step explanation:
The position of the particle moving along the x-axis is given by:

The velocity is given by:

If s'(t)>0 then the particle is moving right.


This means that the particle is moving left when

The particle changes direction at time t=1 or t=11
You have the length of the sides? If not: a and b is the length of the scratch, h is the height <span>This lateral surface area = 2ah+2bh=2h(a+b)</span>
Answer:
The correct option is
x equals the square root of w times the sum of w plus z end quantity
Step-by-step explanation:
The parameters given are
ABC = Right triangle, with ∠B = 90° and CA = Hypotenuse = CD + DA
∴ CA = w + z
BA = v
Hence;
x² = (w + z)² - v²
Where:
v² = z² + y²
∴ x² = (w + z)² - (z² + y²)
x² = w² + 2·w·z + z² - z² - y²
x² = w² + 2·w·z - y²
Where:
y² = x² - w²
We have;
x² = w² + 2·w·z - (x² - w²)
x² = w² + 2·w·z - x² + w²
Which gives;
2·x² = 2·w² + 2·w·z
Removing the common factors, we have;
x² = w² + w·z

The correct option is x equals the square root of w times the sum of w plus z end quantity.
Answer:
7 chairs
Step-by-step explanation:
first, i created an equation:
6x+3=4x+17
and then i solved
and got x=7