No,
Step-by-step explanation:
because since each point has a 0 on it. That means the point would lie on a line of a graph. Meaning, it would be in between quadrants, but not in one.
Hello aysha123994 i am sure that it could be 17. if i am wrong forgive me
Answer:
The vertex of the function
is ![(-\frac{1}{2} ,0)](https://tex.z-dn.net/?f=%28-%5Cfrac%7B1%7D%7B2%7D%20%2C0%29)
Step-by-step explanation:
I've graphed this on desmos for a visual
Step-by-step explanation:
Let a = 8 and b = 11. Using the law of cosines, we can write
![c^2 = a^2 + b^2 - 2ab\cos{c}](https://tex.z-dn.net/?f=c%5E2%20%3D%20a%5E2%20%2B%20b%5E2%20-%202ab%5Ccos%7Bc%7D)
![\:\:\:\:=(8)^2 + (11)^2 - 2(8)(11)\cos{37} = 44.44](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%3D%288%29%5E2%20%2B%20%2811%29%5E2%20-%202%288%29%2811%29%5Ccos%7B37%7D%20%3D%2044.44)
![c = 6.67](https://tex.z-dn.net/?f=c%20%3D%206.67)
Now we're going to use the sine to find ![\angle{B}:](https://tex.z-dn.net/?f=%5Cangle%7BB%7D%3A)
![\dfrac{\sin{B}}{b} = \dfrac{\sin{37}}{c}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csin%7BB%7D%7D%7Bb%7D%20%3D%20%5Cdfrac%7B%5Csin%7B37%7D%7D%7Bc%7D)
or
![\sin{B} =\left(\dfrac{b}{c}\right)\sin{37} = 0.992](https://tex.z-dn.net/?f=%5Csin%7BB%7D%20%3D%5Cleft%28%5Cdfrac%7Bb%7D%7Bc%7D%5Cright%29%5Csin%7B37%7D%20%3D%200.992)
or
![B = \sin^{-1}(0.992) = 83.0°](https://tex.z-dn.net/?f=B%20%3D%20%5Csin%5E%7B-1%7D%280.992%29%20%3D%2083.0%C2%B0)
Answer:
288
Step-by-step explanation: