Answer:
The gravitational potential energy of a system is -3/2 (GmE)(m)/RE
Explanation:
Given
mE = Mass of Earth
RE = Radius of Earth
G = Gravitational Constant
Let p = The mass density of the earth is
p = M/(4/3πRE³)
p = 3M/4πRE³
Taking for instance,a very thin spherical shell in the earth;
Let r = radius
dr = thickness
Its volume is given by;
dV = 4πr²dr
Since mass = density* volume;
It's mass would be
dm = p * 4πr²dr
The gravitational potential at the center due would equal;
dV = -Gdm/r
Substitute (p * 4πr²dr) for dm
dV = -G(p * 4πr²dr)/r
dV = -G(p * 4πrdr)
The gravitational potential at the center of the earth would equal;
V = ∫dV
V = ∫ -G(p * 4πrdr) {RE,0}
V = -4πGp∫rdr {RE,0}
V = -4πGp (r²/2) {RE,0}
V = -4πGp{RE²/2)
V = -4Gπ * 3M/4πRE³ * RE²/2
V = -3/2 GmE/RE
The gravitational potential energy of the system of the earth and the brick at the center equals
U = Vm
U = -3/2 GmE/RE * m
U = -3/2 (GmE)(m)/RE
The correct answer to this problem would be that like poles repel and unlike poles attract.
N and N poles repel
S and S poles repel
N and S poles attract
S and N poles attract
Answer: D) like poles repel each other. unlike poles attract each other
I hope this helps!
Answer:
140Ns
Explanation:
From Newton's 2nd law of motion
F = ma
F = m∆v/t
==> Ft = m∆v
impulse = Ft = 400 × 0.35 = 140Ns
Answer:
By leaping.
Explanation:
When free runners run, they also leap. They do this so they can get more distance and air time. Leaping will allow them to get more distance per jump.
Answer:
i think its only John Dalton
Explanation:
