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tankabanditka [31]
3 years ago
8

A spaceship starting from a resting position accelerates at a constant rate of 9.8 meters per second per second. How long and ho

w far will it take the spaceship to reach a speed of 1 percent the speed of light (300,000,000 m/s)
HOW LONG ANSWER CHOICES
A. 3.5 days
B. 35.4 days
C. 354 days
D. 3403 days
HOW FAR ANSWER CHOICES
A. 3.1 × 106 m
B. 2.94 × 108 m
C. 7.8 × 1010 m
D. 4.6 × 1013 m
30 POINTS
Physics
1 answer:
Verizon [17]3 years ago
4 0

Accelerating at 9.8 m/s² means that every second, the speed is 9.8 m/s faster than it was a second earlier.  It's not important to the problem, but this number (9.8) happens to be the acceleration of gravity on Earth.

1% of the speed of light = (300,000,000 m/s) / 100 = 3,000,000 m/s .

Starting from zero speed, moving (9.8 m/s) faster every second,
how long does it take to reach  3,000,000 m/s ?

           (3,000,000 m/s) / (9.8 m/s²)  =  306,122 seconds .
                                                   (That's  5,102 minutes.)
                                                        (That's  85 hours.)
                                                     (That's  3.54 days.)

Speed at the beginning . . . zero .
Speed at the end . . . 3,000,000 m/s
Average speed . . . . . 1,500,000 m/s

Distance = (average speed) x (time)

               = (1,500,000 m/s) x (306,122 sec) = 4.592 x 10¹¹ meters

                                                                     =  459 million kilometers

                         That's like from Earth
                                                  to       Sun
                                                             to    Earth
                                                                    to        Sun. 

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A square is cut out of a copper sheet. Two straight scratches on the surface of the square intersect forming an angle theta. The
GarryVolchara [31]

Answer:

<em>a) increases</em>

Explanation:

Almost all substance or material undergoes expansion due to heating. Heat gives thermal energy to the molecules of a substance increasing their body temperature. The temperature of a substance is the measure of the average kinetic energy of the molecules of that substance. When the temperature of a substance increases, the molecules begin to agitate and try to move far from each other, leading to either a linear, area, or cubic expansion, or all three of them. Metals like copper expand very well on heating, and their expansion is relatively minute, but very observable. When the face of such a copper is scratched to give and angle, heating the copper uniformly will cause the copper to expand, leading to an increase in the angle formed.

5 0
3 years ago
A baseball player friend of yours wants to determine his pitching speed. you have him stand on a ledge and throw the ball horizo
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Answer:

The pitching speed of your friend is 33.20 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

Your friend throw the ball horizontally that means the vertical initial

component of velocity is zero (u_{y}=0).

The ball is thrown from a height 4 meters above the ground.

The height h=u_{y}t+\frac{1}{2}gt^{2}

<u><em>Remember:</em></u> the height is negative value because its below the point of

thrown (initial position)

h = -4 m , u_{y}=0 and g = -9.8 m/s²(downward)

<em>Substitute these values in the rule above</em>

⇒ 4=0-\frac{1}{2}(9.8)t^{2}

⇒ -4 = -4.9t² (multiply both sides by -1)

⇒ 4 = 4.9t² (divide both sides by 4.9)

⇒ 0.81633 = t² (take √ for both sides)

⇒ <em>t = 0.9035</em>

Then the time of the ball to land on the ground is 0.9035 seconds

The range of the ball on the ground is 30 m

The range R=u_{x}*t, where u_{x} is the horizontal

component of the initial velocity

R = 30 meters and t = 0.9035

⇒ 30=u_{x}(0.9035) (divide both sides by 0.9035)

⇒ u_{x}=33.20 m/s

<em>The pitching speed of your friend is 33.20 m/s </em>

4 0
3 years ago
An ore sample weighs 17.50 N in air. When the sample
zysi [14]

Answer with Explanation:

We are given that

Weight of an ore sample=17.5 N

Tension in the cord=11.2 N

We have to find the total volume and the density of the sample.

We know that

Tension, T=W-F_b

F_b=buoyancy force

T=Tension force

W=Weight

By using the formula

11.2=17.5-F_b

F_b=17.5-11.2=6.3 N

F_b=V_{object}\times \rho_{water}\cdot g

Where

V_{object}=Volume of object

\rho_{water}=1000 kgm^{-3}=Density of water

g=9.8 ms^{-2}=Acceleration due to gravity

Substitute the values then we get

6.3=9.8\times 1000\times V_{object}

V_{object}=\frac{6.3}{9.8\times 1000}=6.43\times 10^{-4} m^3

Volume of sample=6.43\times 10^{-4} m^3

Density of sample,\rho_{object}=\frac{Mass}{volume_{object}}

Where mass of ore sample=1.79 kg

Substitute the values then, we get

\rho_{object}=\frac{1.79}{6.43\times 10^{-4}}=2.78\times 10^3 kg/m^3

Density of the sample=2.78\times 10^{3} kgm^{-3}

7 0
3 years ago
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pogonyaev
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5 0
3 years ago
Read 2 more answers
Hi guys i need truly help!
lutik1710 [3]

Answer:

1) 327

2) 3

3) 109

------------

now I'm not 100% sure #4-6 are correct, but if 4 is right then 5 and 6 are, too.

4) 1074

5) 1074 + 109t

6) 2382

Explanation:

7 0
3 years ago
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