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2 years ago

if you had a trapped gas and continued to cool it until the lowest possible temperature is reached the temperature is called

Physics

2 answers:

prisoha [69]2 years ago

7 0

Absolute Zero.

Kelvin 0 is Absolute Zero, the atoms cannot physically become any closer.
Celsius -273.15

Luba_88 [7]2 years ago

4 0

Answer:

Absolute Zero

Explanation:

The lowest limit of thermodynamic temperature is called as absolute zero. By international agreement, on kelvin scale it is 0 K and on Celsius scale it is equal to -273.15° C. This is considered as the lowest possible temperature. At this temperature the particle vibration is minimum and no heat energy remain in the substance.

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An air conditioner running with R-134a on a cycle executed under the saturationdome between the pressure limits of 0.8 MPa and 0

ohaa [14]

Answer:

The COP of the system is = 4.6

Explanation:

Given data

Higher pressure = 1.8 M pa

Lower pressure = 0.12 M pa

Now we have to find out high & ow temperatures at these pressure limits.

Higher temperature corresponding to pressure 1.8 M pa

$T_{H} = 62.9$ °c = 335.9 K

Lower temperature corresponding to pressure 0.2 M pa

$T_{L} = - 10.1$ °c = 262.9 K

COP of the system is given by

$COP = \frac{T_{L} }{T_{H} -T_{L} }$

$COP = \frac{335.9}{335.9 -262.9}$

COP = 4.6

Therefore the COP of the system is = 4.6

8 0

3 years ago

Consider the three dip1acement vectors A = (3i - 3j) m, B = (i-4j) m, and C = (-2i + 5j) m. Use the component method to determin

tia_tia [17]

Answer with Explanation:

We are given that

A=3i-3j m

B=i-4 j m

C=-2i+5j m

a. $D=A+B+C$

$D=3i-3j+i-4j-2i+5j$

$D=2i-2j$

Compare with the vector r=xi+yj

We get x=2 and y=-2

Magnitude= $\mid D\mid=\sqrt{x^2+y^2}=\sqrt{(2)^2+(-2)^2}=2\sqrt 2$ units

By using the formula $\mid r\mid=\sqrt{x^2+y^2}$

Direction: $\theta=tan^{-1}\frac{y}{x}$

By using the formula

Direction of D: $\theta=tan^{-1}(\frac{-2}{2})=tan^{-1}(-1)=tan^{-1}(-tan45^{\circ})=-45^{\circ}$

b.E=-A-B+C

$E=-3i+3j-i+4j-2i+5j$

$E=-6i+12j$

$\mid E\mid=\sqrt{(-6)^2+(12)^2}=13.4$ units

Direction of E= $\theta=tan^{-1}(\frac{12}{-6}=tan^{-1}(-2)=-63.4^{\circ}$

4 0

3 years ago

After traveling for 6.0 seconds, a runner reaches 10m/s. What is the runner's acceleration?

luda_lava [24]

After traveling for 6.0 seconds, a runner reaches 10m/s. What is the runner's acceleration? Answer: 1.67 m/s2

4 0

3 years ago

A traffic accident detective measures the skid marks left by a car, 825kg. He determines that the distance between the point tha

deff fn [24]

Doing a force balance on the car:
ma = Fr
ma = μmg
a = μg
a = 0.3(9.81)
a = 29.43 m/s2

Using the formula:
2ax = v2
2(29.43)(34) = v2
v = 44.74 m/s = 161.05 km/h

The car was going 44.74 m/s or 161.05 kph when the brakes were applied.

7 0

3 years ago

the distance a spring will stretch varies directly with how much weight is attached to the spring. If a spring stretches 11 inch

Paha777 [63]

Direct variation involves ration and proportions, so

you need to set up the proportion:

<span>11 / 75 = x / 65

Cross multiplying:

75x = 11*65

x = (11*65)/75

Solving, we get x = 9.533, </span>

<span>which rounds off to 9.5

Therefore, the spring will stretch up to 9.5 inches with 65 attached.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

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4 0

3 years ago