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AlladinOne [14]
3 years ago
12

When you are paddling a canoe, you push the water backwards with your paddle, which in turn will push you forward. Which law of

motion is being described in this scenario?
A.Law of Inertia
B.Newton's Second Law of Motion
C.Newton's Third Law of Motion
D.Newton's First Law of Motion
Physics
1 answer:
AVprozaik [17]3 years ago
8 0
Newton's third law of motion. Because you are pushing the water backwards which will push you forwards
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How tall would a tower need to be if the period of a pendulum were 30. seconds
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We use the following expression

T = 2*pi *sqrt(l/g)

Where T is the period of the pendulum

l is the length of the pendulum

and g the acceleration of gravity

We solve for l

l = [T/2*pi]² *g = [30s/2*pi]²* 9.8 [m/s²] = 223.413 m

The tower would need to be at least 223.413 m high
4 0
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Calculate the gravitational attraction between two objects which masses are: mass A: 2.5kg, mass B: 5kg. The distance between th
jonny [76]

From the calculation, the gravitational force of attraction is  1.33 * 10^-14 N.

<h3>What is the gravitational force?</h3>

The gravitational force is an attractive force that acts between any two masses.

It is given by;

F = Gm1m2/r^2

F = 6.67 * × 10−11 * 2.5 * 5/(250)^2

F  = 83.4  × 10−11 /62500

F= 1.33 * 10^-14 N

Learn more about gravitational force:brainly.com/question/12528243

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4 0
2 years ago
A pebble is thrown into the air with a velocity of 19/m at an angle of 36 with respect to the horizontal.
kow [346]

Answer:

The maximum height the pebble reaches is approximately;

A. 6.4 m

Explanation:

The question is with regards to projectile motion of an object

The given parameters are;

The initial velocity of the pebble, u = 19 m/s

The angle the projectile path of the pebble makes with the horizontal, θ = 36°

The maximum height of a projectile, h_{max}, is given by the following equation;

h_{max} = \dfrac{\left (u \times sin(\theta) \right)^2}{2 \cdot g}

Therefore, substituting the known values for the pebble, we have;

h_{max} = \dfrac{\left (19 \times sin(36 ^{\circ}) \right)^2}{2 \times 9.8} = 6.3633894140470403035477570509439

Therefore, the maximum height of the pebble projectile, h_{max} ≈ 6.4 m.

3 0
3 years ago
Look at the velocity versus time graph below. What is the magnitude of the displacement of the object after it travels for three
Elza [17]

Answer:

C. 12m

Explanation:

veocity =  \frac{displacement}{time}

from the graph v = 4m/s and t = 3 s

d = vt = 4 × 3 = 12 m

5 0
3 years ago
A horizontal spring is lying on a frictionless surface. One end of the spring is attached to a wall, and the other end is connec
juin [17]

Answer:

Explanation:

Given that:

angular frequency = 11.3 rad/s

Spring constant (k) = = \omega^2  \times m

k = (11.3)² m

k = 127.7 m

where;

x_1 = 0.065 m

x_2  = 0.048 m

According to the conservation of energies;

E_1=E_2

∴

\Big(\dfrac{1}{2} \Big) kx_1^2 =\Big(\dfrac{1}{2} \Big) mv_2^2 + \Big(\dfrac{1}{2} \Big) kx_2^2

kx_1^2 = mv_2^2 + kx_2^2

(127.7 \ m) \times 0.065^2 = v_2^2 + (127.7 \ m) \times 0.048^2

0.5395325 = v_2^2 +0.2942208 \\ \\ 0.5395325  - 0.2942208 = v_2^2 \\ \\  v_2^2 = 0.2453117 \\ \\  v_2 = \sqrt{0.2453117} \\ \\ \mathbf{ v_2 \simeq0.50 \ m/s}

4 0
3 years ago
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