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AlladinOne [14]
3 years ago
12

When you are paddling a canoe, you push the water backwards with your paddle, which in turn will push you forward. Which law of

motion is being described in this scenario?
A.Law of Inertia
B.Newton's Second Law of Motion
C.Newton's Third Law of Motion
D.Newton's First Law of Motion
Physics
1 answer:
AVprozaik [17]3 years ago
8 0
Newton's third law of motion. Because you are pushing the water backwards which will push you forwards
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how long does it take sound to travel the distance between the two microphones? Given.:wave 1 of microphone 1 has T=2 sec and f=
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Explanation:

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3 years ago
A 1.20-m cylindrical rod of diameter 0.570 cm is connected to a power supply that maintains a constant potential difference of 1
nasty-shy [4]

(a) 1.72\cdot 10^{-5} \Omega m

The resistance of the rod is given by:

R=\rho \frac{L}{A} (1)

where

\rho is the material resistivity

L = 1.20 m is the length of the rod

A is the cross-sectional area

The radius of the rod is half the diameter: r=0.570 cm/2=0.285 cm=2.85\cdot 10^{-3} m, so the cross-sectional area is

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The resistance at 20°C can be found by using Ohm's law. In fact, we know:

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- The current at this temperature is I = 18.6 A

So, the resistance is

R=\frac{V}{I}=\frac{15.0 V}{18.6 A}=0.81 \Omega

And now we can re-arrange the eq.(1) to solve for the resistivity:

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(b) 8.57\cdot 10^{-4} /{\circ}C

First of all, let's find the new resistance of the wire at 92.0°C. In this case, the current is

I = 17.5 A

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R=\frac{V}{I}=\frac{15.0 V}{17.5 A}=0.86 \Omega

The equation that gives the change in resistance as a function of the temperature is

R(T)=R_0 (1+\alpha(T-T_0))

where

R(T)=0.86 \Omega is the resistance at the new temperature (92.0°C)

R_0=0.81 \Omega is the resistance at the original temperature (20.0°C)

\alpha is the temperature coefficient of resistivity

T=92^{\circ}C

T_0 = 20^{\circ}

Solving the formula for \alpha, we find

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3 years ago
Light propagate faster through medium “a” than medium “b”
dangina [55]

1) Medium "b" has more optical density

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Explanation:

1)

Refraction occurs when light propagates from a medium into a second medium.

The optical density of a medium is given by its index of refraction, which is defined as:

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Higher index of refraction means higher optical density, and light propagater slower into a medium with higher optical density.

In this problem, light propagates faster through medium "a" than medium "b": this means that medium "a" has lower refractive index of medium "b", and so "b" has more optical density.

2)

We can answer this part by referring to Snell's law, which gives the relationship between the direction of the incident ray and of the refracted ray when light passes through the interface between two media:

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Here we want the direction of propagation of the light ray not to change: this means that it must be

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However, here we have two mediums "a" and "b" with different index of refraction, so

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Therefore the only angle that can satisfy eq.(1) is

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So, the light must hit the surface perpendicular to the interface between the two mediums.

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

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grigory [225]

Answer:

1. it explains what's happening im the universe now

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