Answer:
The maximum height of coin Jake tosses is 15 feet.
Step-by-step explanation:
Given Jake tosses a coin up in the air
and the height of coin is model by h(t)=
To find height of the coin when Jake tosses it:
When a coin is in the hand of Jake, time t=0
Height of coin is h(t)=
h(0)=
h(0)=6 feet.
Therefore, Height of coin at time t=0 is 6.
For maximum height of the coin,
h(t)=
Differentiating both side,
![\frac{d}{dt}h(t)=\frac{d}{dt}[(-16)t^{2} +24t+6]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7Dh%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B%28-16%29t%5E%7B2%7D%20%2B24t%2B6%5D)
![\frac{d}{dt}h(t)=\frac{d}{dt}[(-32)t+24]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7Dh%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B%28-32%29t%2B24%5D)

![\frac{d}{dt}[(-32)t+24]=0](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%5B%28-32%29t%2B24%5D%3D0)
t=
t=
t=0.75
Now,
h(t)=
h(0.75)=
h(0.75)=15 feet.
The maximum height of coin jake tosses is 15 feet.
[tex]8x - x \\ 8 (0)
hope this help
brainliest plz
House/garage numbers? Like what you stick on your house so the postman knows which one is which.
Complete Question:
An object dropped from rest from the top of a tall building on Planet X falls a distance d(t)=13t^2 feet in the first t seconds. Find the average rate of change of distance with respect to time as t changes from t1=2 to t2=10. This rate is known as the average velocity, or speed.
The average velocity as t changes from 2 to 10 seconds is _______ feet/sec?
Answer:

Step-by-step explanation:
Given

Time Interval: (a,b)


Required
Determine the average rate of change (v)
This is calculated as thus:

Substitute values for b and a


Calculate d(10): Substitute 10 for t




Calculate d(2): Substitute 2 for t




The equation
becomes



Hence, the average rate of change is 156ft/s
X=7/4+7/4y ,y∈ (One symbol I can't find but that's what I got)