Complete Question:
An object dropped from rest from the top of a tall building on Planet X falls a distance d(t)=13t^2 feet in the first t seconds. Find the average rate of change of distance with respect to time as t changes from t1=2 to t2=10. This rate is known as the average velocity, or speed.
The average velocity as t changes from 2 to 10 seconds is _______ feet/sec?
Answer:

Step-by-step explanation:
Given

Time Interval: (a,b)


Required
Determine the average rate of change (v)
This is calculated as thus:

Substitute values for b and a


Calculate d(10): Substitute 10 for t




Calculate d(2): Substitute 2 for t




The equation
becomes



Hence, the average rate of change is 156ft/s