Answer:
It's proved below
Step-by-step explanation:
We are given;
- K is the midpoint of JL
- M is the midpoint of LN
By definition of mid points, we can say that;
JK = KL and LM = MN
Now, we are given that JK = MN.
Thus, by substitution, we can deduce that; KL = LM
Thus is because JK can be replaced with KL and MN can be replaced with LM.
Thus, it is proved that KL = LM
Answer:
Yes triangle ABC and DEF are similar.
Step-by-step explanation:
One rule of triangles is that all the angles in a triangle will add up to 180 degrees.
Now, first, you will figure out the remaining angle in triangle ABC.
- Add up 35 and 20. (35 + 20 =55)
- Subtract 55 from 180 (180-55= 125)
- When you add 125, 35, and 20, you get 180, which should happen due to the rule of all angles in a triangle add up to 180.
Now, in triangle DEF, one angle is 125 and the other is 35. To find the other angle add 125 and 35 and subtract the sum of those two numbers from 180.
- 125 + 35 = 160
- 180-160= 20
The remaining angle is 20 degrees
As you can see, triangle ABC shares the same angles as triangle DEF.
This tells you that triangle ABC and triangle DEF are both similar due to the fact that they have the same measurements of triangles.
You can also tell they are similar because two angles in triangle ABC equal two angles in triangle DEF because of the Angle-Angle (AA) Similarity
I hope this explanation helped and have a good day!
Answer:
Step-by-step explanation:
difference means subtract.
The 24 is mentioned first so it is written first.
Then comes the minus sign
Then the number (x)
24 - x
The solution (-4,2) satisfies for the system of linear equations 3x + 13y = 14; 6x + 11y = -2
<u>Step-by-step explanation:</u>
Step 1:
Given detail is the solution of the equations (-4, 2) ie, x= - 4 and y = 2
This implies that this solution should satisfy the given linear equations.
Step 2:
Substitute values of x and y in the equations and verify whether the right hand side equals the left hand side.
System 1 Eq(1) ⇒ LHS = 3(-4) + 13 (2) = -12 + 26 = 14 = RHS
System 1 Eq(2) ⇒ LHS = 6(-4) + 11(2) = -24 + 22 = -2 = RHS
Therefore, the first system of linear equations satisfy the condition.
Given:
Principal = ₹ 5000
Compound rate of interest = 6% per annum
Time = 3 years
To find:
The amount after 3 years of compound interest.
Solution:
Formula for amount is:
Where, P is principal, r is rate of interest in % and t is the number of years.
Putting P=5000, r=6 and t=3, we get
On further simplification, we get
Therefore, the amount after 3 years of compound interest is 5955.08.
