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3 years ago

Algebra: Solve for x

Mathematics

2 answers:

marta [7]3 years ago

7 0

Answer:

x = -2

Step-by-step explanation:

$\frac{6- -2}{2} = 4\\\\\frac{6+2}{2} = 4\\\\\frac{8}{2} = 4\\\\4 = 4$

Chow,...!

Irina-Kira [14]3 years ago

5 0

Answer:

Step-by-step explanation:

6-x/2=4

6-x=4*2

6-x=8

x=2

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Can someone help me please im confused

Kruka [31]

Interesting, have you tried Wikipedia?

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3 years ago

CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION? 4x+2=7x-37

grin007 [14]

<h2>Answer:</h2><h2>x = 13</h2><h2 /><h2>Hope this helps!!</h2>

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2 years ago

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Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

<em>Number of projects in the first year = 90</em>

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

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2 years ago

(1, 3) and (-3, -5)<br> write a linear equation given the two points

Firlakuza [10]

Answer:

y = 2x + 1

Step-by-step explanation:

1. Find the slope; (change in y values)/(change in x values)

Slope = (-5 - 3)/ (-3 - 1) = -8/-4 = 2

2. Find the y-intercept (b) using the slope intercept formula: y = mx + b

m = 2 and using point (1, 3) , solve for "b"

y = mx + b

3 = 2(1) + b

3 = 2 + b

1 = b

3. Write the linear equation: y = 2x + 1

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2 years ago

Solve.

Serhud [2]

Answer:

Step-by-step explanation:

12.9 + 10.2x = 35.1

10.2x = 35.1 - 12.9

10.2x = 22.2

x = 22.2/10.2

x= 222/102 = 111/51

$x= 2\dfrac{9}{51}$

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2 years ago

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