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3 years ago

Algebra: Solve for x

Mathematics

2 answers:

marta [7]3 years ago

7 0

Answer:

x = -2

Step-by-step explanation:

$\frac{6- -2}{2} = 4\\\\\frac{6+2}{2} = 4\\\\\frac{8}{2} = 4\\\\4 = 4$

Chow,...!

Irina-Kira [14]3 years ago

5 0

Answer:

Step-by-step explanation:

6-x/2=4

6-x=4*2

6-x=8

x=2

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A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish

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Answer:

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Similarly x' : y' = 333 : 444

⇒ $\frac{x'}{y'}=\frac{333}{444}$

⇒ $\frac{x'}{y'}=\frac{3}{4}$

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Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

$\frac{x+y}{x'+y'}=\frac{464646}{555}$

Now we replace the values of x and y' from equation (1) and equation (2)

$\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}$

$\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}$

$\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}$

$\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}$

$\frac{x}{y'}=\frac{232323}{370}$

$\frac{y'}{x}=\frac{370}{232323}$

$\frac{y'}{x}=\frac{10}{6279}$

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

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