What’s the equation for f and g?
2 answers:
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Like terms have the same variable and power. The simplification of the expression (6x²-3-5x³)-(4x³+2x²-8) is -9x³+4x²+5.
<h3>What are Like terms?</h3>Like terms are those terms that are having the same variables, also the variables are of the same order as well.
for example, 25x and 5x are like terms; 30xy and 7xy are like terms, 9x³ and 4x² are not like terms, etc.
We know that to simplify an expression we need to add or subtract like terms, therefore,
Hence, the simplification of the expression (6x²-3-5x³)-(4x³+2x²-8) is -9x³+4x²+5.
Learn more about Like Terms:
(See attached formula)
Years = log (total / principal) / n*log(1 + rate/n) where n = compounding periods per year
Years = log (total / principal) / n*log(1 + rate/n)
Rate of .75% = .0625 per month
We'll say we want total = 200 and principal = 100
Years = log (200 / 100) / 12*log(1 + rate/n)
Years = log (2) / 12 * log (1 + .0625/12)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 * <span> <span> <span> 0.0022560803 </span> </span> </span> <span><span> </span> </span>
Years = <span> <span> 0.3010299957 </span> </span> / <span> <span> <span> 0.0270729635 </span>
Years = </span></span><span><span><span>11.1192110871 </span> </span> </span>
I don't think that's right
The interest rate is REALLY low. (Less than 1%)
Rate = .75 and .0075 when in a formula
Years = log (2) / 12 * log (1 + .0075/12)
Years = log (2) / 12 * log( <span>1.000625</span>)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 * <span> <span> <span> 0.0002713493 </span> </span> </span>
Years = <span><span><span> <span> 0.3010299957 </span> </span> / 0.0032561912 </span>
</span>Years = <span><span><span>92.4485010892
THAT seems a more likely answer with such a low interest rate.
</span> </span> </span>
Years = log (total / principal) / n*log(1 + rate/n) where n = compounding periods per year
Years = log (total / principal) / n*log(1 + rate/n)
Rate of .75% = .0625 per month
We'll say we want total = 200 and principal = 100
Years = log (200 / 100) / 12*log(1 + rate/n)
Years = log (2) / 12 * log (1 + .0625/12)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 * <span> <span> <span> 0.0022560803 </span> </span> </span> <span><span> </span> </span>
Years = <span> <span> 0.3010299957 </span> </span> / <span> <span> <span> 0.0270729635 </span>
Years = </span></span><span><span><span>11.1192110871 </span> </span> </span>
I don't think that's right
The interest rate is REALLY low. (Less than 1%)
Rate = .75 and .0075 when in a formula
Years = log (2) / 12 * log (1 + .0075/12)
Years = log (2) / 12 * log( <span>1.000625</span>)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 * <span> <span> <span> 0.0002713493 </span> </span> </span>
Years = <span><span><span> <span> 0.3010299957 </span> </span> / 0.0032561912 </span>
</span>Years = <span><span><span>92.4485010892
THAT seems a more likely answer with such a low interest rate.
</span> </span> </span>
I don’t understand you second question but this is the work for the first one.
Hope it helps!
Hope it helps!