Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
Both, depends on the place in which you live
Answer:
ijsdbf
dsad
Stepdvds-by-step explanation:
d
6.6666 rounded to the nearest thousandth is 6.667.
The number in the ten thousandths place is greater than five, so the 6 in the thousandths place rounds up to a seven
It is the graph of f(x) = x^2 vertically compressed, and then translated 3 units up and 5 units to the right.
<h3>Transformation techniques</h3>
Transformation is a process of changing the size and shape of an object. The given graph is a graph of quadratic function with parent function x².
According to the graph shown the resulting parent function has been shifted horizontally to the right by 5 units to produce g(x) = f(x) - 5
Learn more on translation here: brainly.com/question/12861087
#SPJ1