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SVEN [57.7K]
3 years ago
13

Will mark as Brainlist!

Mathematics
1 answer:
ASHA 777 [7]3 years ago
8 0

Answer:

y=1/4x + 16

Step-by-step explanation:

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Polygon X is similar to polygon Y. Polygon X is three times the size of polygon Y. The perimeter of polygon X is 81. What is the
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Answer:  Option 'C' is correct.

Step-by-step explanation:

Since we have given that

Polygon X is similar to polygon.

And Polygon X is three times the size of polygon Y.

So, it becomes,

\dfrac{\text{Perimeter of polygon X}}{\text{Perimeter of polygon Y}}=\dfrac{3}{1}\\\\\dfrac{81}{x}=\dfrac{3}{1}\\\\x=\dfrac{81}{3}\\\\x=27

Hence, perimeter of polygon Y is 27.

Therefore, Option 'C' is correct.

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3 years ago
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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
OM , ON and OP are the angle bisectors of ∠AOB, ∠BOC, and ∠COD respectively. ∠AOD and ∠BOE are straight angles.
Orlov [11]

Find m∠BOC, if m∠MOP = 110°.

Answer:

m∠BOC= 40 degrees

Step-by-step explanation:

A diagram has been drawn and attached below.

  • OM bisects AOB into angles x and x respectively
  • ON bisects ∠BOC into angles y and y respectively
  • OP bisects ∠COD into angles z and z respectively.

Since ∠AOD is a straight line

x+x+y+y+z+z=180 degrees

2x+2y+2z=180^\circ

We are given that:

m∠MOP = 110°.

From the diagram

∠MOP=x+2y+z

Therefore:

x+2y+z=110°.

Solving simultaneously by subtraction

2x+2y+2z=180^\circ

x+2y+z=110°.

We obtain:

x+z=70°

Since we are required to find ∠BOC

∠BOC=2y

Therefore from x+2y+z=110° (since x+z=70°)

70+2y=110

2y=110-70

2y=40

Therefore:

m∠BOC= 40 degrees

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3 years ago
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