3 years ago

PLEASE HELP ME WITH THE SECOND ONE ;(

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

8 0

Im pretty sure it’s joint

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vovikov84 [41]

A = {1, 3, 5, 7, 9}
B = {2, 4, 6, 8, 10}
C = {1, 5, 6, 7, 9}

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3 years ago

A survey of 46 college athletes found that 24 played volleyball, while 22 played basketball. a) If we pick one athlete survey pa

PSYCHO15rus [73]

Answer:

A) $\dfrac{11}{23}$

B) $\dfrac{88}{345}$

Step-by-step explanation:

A survey of 46 college athletes found that

24 played volleyball,
22 played basketball.

A) If we pick one athlete survey participant at random, the probability they play basketball is

$P_1=\dfrac{22}{46}=\dfrac{11}{23}$

B) If we pick 2 athletes at random (without replacement),

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Thus, the probability we get one volleyball player and one basketball player is

$P_2=\dfrac{12}{23}\cdot \dfrac{22}{45}=\dfrac{88}{345}$

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3 years ago