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yarga [219]
3 years ago
7

A 16-foot ladder is placed against the side of a building. The bottom of the ladder is 8 foot from the base of the building. In

order to increase the reach of the ladder against the building, they moved the ladder four foot closer to the building. To the nearest foot, how much further up the building does the ladder now reach?
Mathematics
2 answers:
OLEGan [10]3 years ago
5 0
8 feet
Hope I helped!
vagabundo [1.1K]3 years ago
3 0

Answer:

Subtract 15.49 - 13.86 = 1.63 and then you simplify.

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Write a real life scenario that could be represented by this equation:
Vsevolod [243]

Answer:

You can use it to graph something on a piece of paper or solve an environmental problem or you can use it to multiply apple slices in a recipe of apple pie.

3 0
3 years ago
If DE = 7x + 3 and EF = 9x - 19,<br> then EF = ?
ANEK [815]

Answer:

Step-by-step explanation:

7x + 3 = 9x - 19

-2x + 3 = -19

-2x = -22

x = 11

DE= 7(11) + 3 = 77 + 3 = 80

EF = 9(11) - 19 = 99 - 19 = 80

80 + 80 = 160 for DF

6 0
3 years ago
The median income for a sample of people from Chicago is about $60,000 and the
Serhud [2]

Answer:

106,000 is the answer help me with my answer to

5 0
3 years ago
Read 2 more answers
1.what is a sports car average acceleration if it can go from 0m/s to 27m/s in 6.0 seconds?
Flauer [41]

Answer:

1.4.5m/s^2

2.6.25m/s^2

3.15m/s^2

4.0.05m/s^2

Step-by-step explanation:

a=v-u

----

t

27-0

------ = 27/6

6

=4.5m/s^2

u=4.5m/s

v=24.5m/s

t=3.2s

(24.5-4.5)÷3.2

=20/3.2

=6.25m/s^2

v=80m/s

u=50m/s

t=2s

(80-50)÷2

15m/s^2

v=0.80m/s

u=0.50m/s

t=6s

(0.80-0.50)÷6

=0.05m/s^2

5 0
2 years ago
2p^2+10=0 <br><br> Please help!
ohaa [14]
2p^2+10=0\ \ \ |-10\\\\2p^2=-10\ \ \ |:2\\\\p^2=-5
No real solutions, because for all real numbers the square of number is greater or equal 0.


7 0
3 years ago
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