We have the following dimensions:
w=wide
w+70=length
We have a right triangle:
leg₁=w
leg₂=w+70
hypotenuse=130
Pythagoras theorem:
leg₁²+leg₂²=hypotenuse²
Then:
w²+(w+70)²=130²
We have to solve that equation:
w²+(w+70)²=130²
w²+w²+140w+4900=16900
2w²+140w+4900-16900=0
2w²+140w-12000=0
(2w²+140w-12000)/2=0/2
w²+70w-6000=0
w=(-70⁺₋√(4900+24000)) / 2
=(-70⁺₋170) / 2
We have two possible solutions:
Solution 1
w=(-70-170)/2=-120 (this solution is not possible because the result is negative and it have no sense in this problem).
Solution 2
w=(-70+170)/2=50 (this is the right solution)
w=50
w+70=120
ANSWER: the length would be 120 u (u=units of length ) and the wide would be 50 u.
Answer:
Step-by-step explanation:
3
It would be 123,456,789 (if not counting decimals)
decimals would be like 0.123456789
Answer:
c correct
Step-by-step explanation:
1: answer: 4^6 ( reduce the fraction with 4^3)
2: answer: 1 ( any nonzero expression raised to the power of 0 equals 1 )
3: answer 3^8
steps: (3^2)^4 = 3^2×4 ( to raise a power to another Power multiply the exponents)
3^2×4 = 3^8 ( multiply the 2 and the 4 exponent to get a 8 as a exponent )
