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Darina [25.2K]
4 years ago
13

(n^(4))/(n^(4)) what does that equal?

Mathematics
1 answer:
sesenic [268]4 years ago
8 0

Answer:

the answer would be 1 happy to help ya :)

Step-by-step explanation:

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The product of two consecutive odd integers is 255. Find the integers.
Grace [21]

Answer:

255 5,6 7,78

Step-by-step explanation:

5 0
3 years ago
NEED CORRECT ANSWER PLEASE! THANKS:)
-BARSIC- [3]
The answer is B. (2x + 5)(x + 1)You could answer this by expanding each answer until you found one that matched 2x^2 + 7x + 5, but I will only show how the answer expands:
2x × x = 2x^2
5 × x = 5x
2x × 1 = 2x
5 × 1 = 5

So in total those brackets expand to 2x^2 + 7x + 5. I hope this helps!
6 0
3 years ago
Write two equivalent equations for the equation 3f+2m=16.
vaieri [72.5K]

Answer:

16=3f+2m

16-2m=3f

Step-by-step explanation:

3 0
3 years ago
What is the square root of 539?
Mama L [17]
You would use 539 and square it on you cal. just once. Then once you do that the answer is not going to be a whole number it is going to have a decimal, so the answer would be 23.22. 
6 0
3 years ago
Read 2 more answers
Calculus piecewise function. ​
Kipish [7]

Part A

The notation \lim_{x \to 2^{+}}f(x) means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows \lim_{x \to 2^{+}}f(x) = 2

Then for the left hand limit \lim_{x \to 2^{-}}f(x), we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, \lim_{x \to 2^{-}}f(x) = 1

===============================================================

Part B

Because \lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x) this means that the limit \lim_{x \to 2}f(x) does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since \lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3, this means the limit \lim_{x \to 4}f(x) does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0
2 years ago
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