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Setler [38]
3 years ago
10

How do I write 9x-7y=-7 in slope intercept form?

Mathematics
2 answers:
kvv77 [185]3 years ago
8 0
The slope-intercept form: y= mx + b

9x - 7y = -7    |subtract 9x from both sides

-7y = -9x - 7    |divide both sides by (-7)

y = 9/7x + 1
taurus [48]3 years ago
8 0
9x-7y=-7
Rewriting it in the form y=mx+c
7y=9x+7
y=\frac{9}{7} x+1
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Step-by-step explanation:

The augmented matrix of the system of linear equation is described below:

\left[\begin{array}{cccc}2&1&-1&-8\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]

Where a_{11} = 2, if we need to create a_{11} = 1, we need to multiply row 1 by \frac{1}{2}, that is to say:

\left[\begin{array}{cccc}1&\frac{1}{2} &-\frac{1}{2} &-4\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]

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