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attashe74 [19]
3 years ago
8

Question 11 (1 point)

Chemistry
1 answer:
erastova [34]3 years ago
5 0

Answer:

remove product

Explanation:

Removing the product will always shift the equilibrium to the right. This is based on the Le Chatelier's principle which states that "if any of the conditions of a system in equilibrium is changed, the system will adjust itself in order to annul the effect of the change".

  • If a system at equilibrium is disturbed, by changing the concentration of one of the substances all the concentrations will change until a new equilibrium point is reached.
  • Removing the product will increase the concentration of the species on the left hand side, the equilibrium will shift to the right.
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something

Explanation:

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Determine molar mass of Mn (ClO3)3
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M(Mn(ClO3)3)=(54.938)+(35.45x3)+(15.999x9)
M(Mn(ClO3)3)=305.279 g/mol
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Which is the correct name for the compound Ca(CLO2)2
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Calcium hypochlorite
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Calculate the DH°rxn for the decomposition of calcium carbonate to calcium oxide and carbon dioxide. DH°f means delta or change
USPshnik [31]

Answer: +178.3 kJ

Explanation:

The chemical equation  follows:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(CaO(s))})+(1\times \Delta H^0f_{CO_2}]-[(1\times \Delta H^o_f_{(CaCO_3(s))})]

We are given:

\Delta H^o_f_{(CaO(s))}=-635.1kJ/mol\\\Delta H^o_f_{(CaCO_3(s))}=-1206.9kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_{rxn}=?

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-635.1))+(1\times (-393.5))]-[(1\times (-1206.9))]

The DH°rxn for the decomposition of calcium carbonate to calcium oxide and carbon dioxide is +178.3 kJ

5 0
3 years ago
A gas has a pressure of 0.12 atm at 294 K. What is the new pressure at 273 K?​
seropon [69]

Answer:

P₂ = 0.11 atm

Explanation:

Given data:

Initial pressure = 0.12 atm

Initial temperature = 294 K

Final pressure = ?

Final temperature = 273 K

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

0.12 atm / 294 K = P₂/273 K

P₂ = 0.12 atm × 273 K / 294 K

P₂ = 32.76 atm. K /294 K

P₂ = 0.11 atm

5 0
2 years ago
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