Answer:
1.8 moles of O₂
Explanation:
The balance chemical equation for said double replacement (photosynthesis) reaction is as follow;
6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂
According to balance chemical equation,
6 moles of O₂ are produced by = 6 moles of CO₂
So,
1.8 moles of O₂ will be produced by = X moles of O₂
Solving for X,
X = 1.8 mol × 6 mol / 6 mol
X = 1.8 moles of O₂
Stoichiometric problems in which moles are given and moles or other reactant or product asked are the simplest problems. One should only write the balanced chemical equation and perform above method to find the required moles.
Answer:
a. the solution is a base
Explanation:
The pH range is between 0 to 14.
A solution with a pH value between 0 and 6 is said to be acidic.
A solution with pH value at 7, is said to be neutral, e.g., distilled water.
A solution with pH value between 8 and 14 is a base.
Given pH = 10, a pH value of 10 falls between the base or alkali range of the indicator
Answer:
6750 J
Explanation:
The specific heat capacity of iron is 450 J/kg/K
Quantity of heat = mcθ; where m is the mass and c is the specific heat capacity and θ is the temperature change.
Therefore;
m = 3 kg, c = 450 J/kg/K and θ = 5°C
Quantity of heat = 3 × 450 × 5
<u>= 6150 Joules</u>
The percent composition of the compound is 79.87 % of carbon and 20.12% of hydrogen
Explanation:
Given:
mass of carbon = 13.18 grams
mass of hydrogen = 3.32 grams
percent composition of compound =?
From the given data total mass of the compound is calculated
13.8 + 3.32
= 16.5 grams
The individual percentage of hydrogen and carbon will be calculated as:
percent composition = 
x 100
For carbon,
x 100
percent composition of carbon = 79.87 % of carbon.
for hydrogen:
= 20.12 % of hydrogen
In the compound given 79.87 % of carbon and 20.12% of hydrogen is present.
Answer:
1.5 mol
Explanation:
Step 1: Given data
- Volume of argon gas: 33 L
- Standard temperature: 273.15 K
Step 2: Calculate the moles corresponding to 33 L of argon at standard temperature and pressure (STP)
At STP, 1 mole of argon gas occupies 22.4 L.
33 L × 1 mol/22.4 L = 1.5 mol
