Maybe use flash cards for them to understand or look up periodic table on line and show them.
p [OH-] = -log[OH-]= -log ( 1x10^-11M) = 11
we know that
p[OH-] + p[H+] = 14
so p[H+] = 14- p[OH-] = 14- 11 = 3
pH = 3, answer
Answer:
I
Explanation:
Among the halogens given in this problem, iodine has the lowest attraction for electrons.
This property is known as electronegativity.
Electronegativity is expressed as the relative tendency with which the atoms of the element attracts valence electrons in a chemical bond.
- As you go down the periodic group the electronegativity decreases.
- The most electronegative element on the periodic table is fluorine.
- Down the group, iodine is the least electronegative
- This is due to the large size of its atom.
Answer: Magnesium hydroxide, Mg(OH)2
Explanation:
2HC2H3O2(aq) + Mg(OH)2(aq) → Mg(C2H2O2)2(aq) + 2H2O(l)
Acid + base → Salt + Water.
The equation above is an example of an acid-base reaction where the acid, aqeous 2HC2H3O2 reacts completely with an appropriate amount of the base, aqueous Mg(OH)2 to produce salt, aqueous Mg(C2H2O2)2 and water, liquid H2O only.
This acid-base reaction is also known as neutralization reaction.
