Ask question

Ask question

All categories

3 years ago

14

If the family decreases the clothing budget by 3 percent, what amount will it have to spend on clothing? Round to the nearest do

llar.

1 answer:

Contact [7]3 years ago

5 0

What is there initial budget? and then take that and multiply by .3 and the. subtract that number from the original budget and you get your answer

You might be interested in

What would happen to the equilibrium mixture if the chlorine gas was allowed to escape? (explain your answer )

almond37 [142]

<span>Mimicupcakes650 Beginner answered 5 minutes ago ... What would happen to the equilibrium mixture if the chlorine gas was allowed to escape? (explain your answer ) from Gabbymarriott. 1 answer ... Describe the physical and chemical properties of the raft that would be important to ensure your safety. from Dustyy.</span>

6 0

3 years ago

What describes the solvent in any solution

Lady_Fox [76]

Solvent is more than a solute. Like salt water. Water is the solvent and salt will be the solute

5 0

2 years ago

Read 2 more answers

How many moles of CaCl₂ are required to produce 45.97 grams of NaCl?

marin [14]

Answer is 0.7866187543

6 0

2 years ago

poizon [28]

So, what's your question..?. You just gave options..

8 0

2 years ago

Read 2 more answers

An archaeologist graduate student found a leg bone of a large animal during the building of a new science building. The bone had

Vlad [161]

Answer : The time passed in years is $2.74\times 10^2\text{ years}$

Explanation :

Half-life of carbon-14 = 5730 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{5730\text{ years}}$

$k=1.21\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.21\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = ?

a = initial amount of the reactant disintegrate = 15.3

a - x = amount left after decay process = 14.8

Now put all the given values in above equation, we get

$t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{15.3}{14.8}$

$t=274.64\text{ years}=2.74\times 10^2\text{ years}$

Therefore, the time passed in years is $2.74\times 10^2\text{ years}$

4 0

3 years ago