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Lostsunrise [7]
3 years ago
15

Can someone help me ????

Chemistry
2 answers:
agasfer [191]3 years ago
7 0

Answer:

\boxed {\boxed {\sf Cobalt, Iron, and \  Copper}}

Explanation:

The Stock System states that In a chemical formula or equation, some metals need a roman numeral after their symbol. If a metal has <u>multiple oxidation states</u>, it needs a roman numeral.

Use the Periodic Table to see the oxidation states for each metal.

  • Cobalt (Co): +3, +2
  • Lithium (Li): +1
  • Barium (Ba): +2
  • Iron (Fe): +3, +2
  • Copper (Cu): +2, +1
  • Potassium (K): +1

We can see that <u>cobalt, iron, and copper</u> have more than one oxidation state, so they would require a roman numeral.

Alexandra [31]3 years ago
4 0

Answer:

B) Lithium

C) Barium

F) Potassium

Explanation:

All of the above are Inorganic Compounds.

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Pressure gauge at the top of a vertical oil well registers 140 bars. The oil well is 6000 m deep and filled with natural gas dow
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Explanation:

(a)  The given data is as follows.

              Pressure on top (P_{o}) = 140 bar = 1.4 \times 10^{7} Pa       (as 1 bar = 10^{5})

              Temperature = 15^{o}C = (15 + 273) K = 288 K

         Density of gas = \frac{PM}{ZRT}

                \frac{dP}{dZ} = \rho \times g

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                \int_{P_{o}}^{P_{1}} \frac{dP}{dZ} = \frac{Mg}{ZRT} \int_{0}^{4700} dZ

           ln (\frac{P_{1}}{P_{o}}) = \frac{18.9 \times 10^{-3} \times 9.81 \times 4700 m}{0.80 \times 8.314 J/mol K \times 288 K}

                              = 0.4548

                     P_{1} = P_{o} \times e^{0.4548}

                                 = 1.4 \times 10^{7} Pa \times 1.5797

                                 = 2.206 \times 10^{7} Pa

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                 P_{2} = P_{1}  + \rho \times g \times h

                             = 2.206 \times 10^{7} Pa + 700 \times 9.81 \times (6000 - 4700)[/tex]

                             = 309.8 \times 10^{5} Pa

                             = 309.8 bar

Hence, at the bottom of the well at 15^{o}C pressure is 309.8 bar.

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Imaging that for assembling a toy you have process of three steps:

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