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Artist 52 [7]
3 years ago
11

***I NEED HELP ASAP*** ***Please show all the steps*** ***I will mark brainliest***

Mathematics
1 answer:
mixer [17]3 years ago
3 0

Answer:

First on is 0.75

Second is 22/52 (not sure about this one though)

Step-by-step explanation:

For the first one:

P(aUb) = p(a) + p(b) - p(a^b)

0.6 = 0.4 + 0.5 - p(a^b)

p(a^b) = 0.3

P(a/b)= p(a^b)/p(a)

P(a/b)= 0.3/0.4

P(a/b)= 0.75

For the second one:

Total of the cards are 52

Diamonds are 13 out of that 52

Face cards are 12 out of that 52

Diamond OR face cards means p(aUb)

And that equals p(a)+p(b)-p(a^b)

p(a^b) means the intersection between the two, there are three common cards between diamonds and face cards, so p(a^b)=3

13/52 + 12/52 - 3/52= 22/52

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Watch help video
Evgen [1.6K]

Answer:

20 dimes and 2  quarters

Step-by-step explanation:

x = number of dimes

y  = number of quarters

minimum is greater than or equal to ≥

x+y ≥16

no more than is less than or equal to ≤ ,

value of dime is $ 0.10

value of quarter is $0.25 so

0.10x + 0.25y ≤ 3.00

Rewrite inequalities in terms of y:

y ≥16 - x

(0.25/0.25)y ≤ (3.00/0.25)-(0.10/0.25)x→

y≤12 - 0.4x

Graph system: see file

6 0
3 years ago
How can "12 of 40" be written as a simplified ratio?
vitfil [10]
<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ 12 : 40

==> 3 : 10

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

5 0
3 years ago
Read 2 more answers
A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded
Crank

Answer:

A=81(\pi-1)\ in^2

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

A=\pi r^{2}

we have

r=18/2=9\ in ---> the radius is half the diameter

substitute

A=\pi (9)^{2}\\A=81\pi\ in^2

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

D^2=2b^2

where

b is the length side of the square

we have

D=18\ in

substitute

18^2=2b^2

solve for b^2

b^2=162\ in^2 -----> is the area of the square

Divide by 2

162/2=81\ in^2

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The  area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

so

A=(81\pi-81)\ in^2

simplify

A=81(\pi-1)\ in^2

8 0
3 years ago
I am so confused right now plz help me
Maksim231197 [3]
You have to remember P.E.M.D.A.S. when doing problems like this.
Drew used PEMDAS so we know he isn't wrong. However, Sam didn't use PEMDAS. She multiplied 2&5 instead of raising 5 to the second. 
The correct answer for Sams' problem would be 30.
Hope this helps! :)
3 0
3 years ago
Simplify 15(5b+3)<br> Please help me I don't understand at all
melamori03 [73]
15(5b+3) \\ \\ 15 \times 5b + 15 \times 3 \ / \ distribute \\ \\ 75b + 15 \times 3 \ / \ simplify \\ \\ 75b + 45 \ / \ simplify \\ \\

The final result is: 75b + 45.
3 0
3 years ago
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