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3 years ago

Adrian says that 4(-9)= 36. Why is Adrian incorrect?

Mathematics

1 answer:

xenn [34]3 years ago

4 0

Answer:

4(-9)= -36

Step-by-step explanation:

Since there's a negative on the 9 it will affect the product. So the answer is supposed to be a - 36.

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You've saved up $97 to buy a new guitar. The guitar you want costs $125. Write an inequality.

Allushta [10]

Answer:

97 - is less than 125 Or 97 + x = 125

Step-by-step explanation:

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7 0

3 years ago

If cot 0= 1.5 find tan 0 a. 1/1.5 b1.5 c.1/3 d.1/4.5= 0.2222

Zepler [3.9K]

Answer:

tan θ = $\frac{1}{1.5}$

Step-by-step explanation:

We are given that cot θ = 1.5 and cotangent is the cofunction of tangent.

cot θ = $\frac{adjacent}{opposite}$

tan θ = $\frac{opposite}{adjacent}$

We can find the answer to tan θ by taking the reciprocal of the answer to cot θ.

cot θ = 1.5

Then, tan θ = $\frac{1}{1.5}$

5 0

3 years ago

Read 2 more answers

A yo-yo is moving up and down a string so that its velocity at time t is given by v(t) = 3cos(t) for time t ≥ 0. The initial pos

jeka57 [31]

Part A - The average value of v(t) over the interval (0, π/2) is 6/π

Part B - The displacement of the yo-yo from time t = 0 to time t = π is 0 m

Part C - The total distance the yo-yo travels from time t = 0 to time t = π is 6 m.

<h3>Part A: Find the average value of v(t) on the interval (0, π/2)</h3>

The average value of a function f(t) over the interval (a,b) is

$f(t)_{avg} = \frac{1}{b - a} \int\limits^b_a {f(t)} \, dx$

So, since velocity at time t is given by v(t) = 3cos(t) for time t ≥ 0. Its average value over the interval (0, π/2) is given by

$v(t)_{avg} = \frac{1}{\frac{\pi }{2} - 0} \int\limits^{\frac{\pi }{2} }_0 {v(t)} \, dt$

Since v(t) = 3cost, we have

$v(t)_{avg} = \frac{1}{\frac{\pi }{2} - 0} \int\limits^{\frac{\pi }{2} }_0 {3cos(t)} \, dt\\= \frac{3}{\frac{\pi }{2}} \int\limits^{\frac{\pi }{2} }_0 {cos(t)} \, dt\\= \frac{6}{{\pi}} [{sin(t)}]^{\frac{\pi }{2} }_{0} \\= \frac{6}{{\pi}} [{sin(\frac{\pi }{2})} - sin0]\\ = \frac{6}{{\pi}} [1 - 0]\\ = \frac{6}{{\pi}} [1]\\ = \frac{6}{{\pi}}$

So, the average value of v(t) over the interval (0, π/2) is 6/π

<h3>Part B: What is the displacement of the yo-yo from time t = 0 to time t = π?</h3>

To find the displacement of the yo-yo, we need to find its position.

So, its position x = ∫v(t)dt

= ∫3cos(t)dt

= 3∫cos(t)dt

= 3sint + C

Given that at t = 0, x = 3. so

x = 3sint + C

3 = 3sin0 + C

3 = 0 + C

C = 3

So, x(t) = 3sint + 3

So, its displacement from time t = 0 to time t = π is

Δx = x(π) - x(0)

= 3sinπ + 3 - (3sin0 + 3)

= 3 × 0 + 3 - 0 - 3

= 0 + 3 - 3

= 0 + 0

= 0 m

So, the displacement of the yo-yo from time t = 0 to time t = π is 0 m

<h3>Part C: Find the total distance the yo-yo travels from time t = 0 to time t = π. (10 points)</h3>

The total distance the yo-yo travels from time t = 0 to time t = π is given by

$x(t) = \int\limits^{\pi}_0 {v(t)} \, dt\\= \int\limits^{\pi }_0 {3cos(t)} \, dt\\= 3 \int\limits^{\pi }_0 {cos(t)} \, dt\\ = 3 \int\limits^{\frac{\pi }{2} }_0 {cos(t)} \, dt + 3\int\limits^{\pi }_{\frac{\pi }{2}} {cos(t)} \, dt\\= 3 \times 2\int\limits^{\frac{\pi }{2} }_0 {cos(t)} \, dt\\= 6 [{sin(t)}]^{\frac{\pi }{2} }_{0} \\= 6[{sin\frac{\pi }{2} - sin0]\\\\= 6[1 - 0]\\= 6(1)\\= 6$

So, the total distance the yo-yo travels from time t = 0 to time t = π is 6 m.

Learn more about average value of a function here:

brainly.com/question/15870615

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4 0

1 year ago

Solve x/4 > 2 ............... Thank you :)

VikaD [51]

x/4 > 2

Simplify by multiplying 4 on both sides

x>8

Which is,

<h2><u><em>THE SECOND OPTION</em></u></h2>

<u><em>-Hunter</em></u>

8 0

2 years ago

27 is 15% of what number

Sedaia [141]

27 is 15% of 180
(15/100)*x=27
x=27 / (15/100)
x=(27 * 100) / 15
x=180

6 0

3 years ago