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3 years ago

A triangle has one leg that measures 14 feet and the hypotenuse is 50 feet. What is the length of the other leg?

1 answer:

8 0

Ok so we are using the Pythagorean theorem so were gonna do A^2 + B^2 = C^2

It don't say which leg we have so you can use either a or b.
Which would get us 14^2 + B^2 = 50^2
14*14 =196 , 50 *50 =2500
Then we have to subtract the two.
So 2500 - 196 = 2,304
Then you take the take the square root of that answer and you have your other leg.
The square root of 2,304 is 48
So the missing leg = 48

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SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: State the number of outcomes possible for three tossing of a coin

Since a coin has two possible outcomes and is tossed three times, the total outcomes will be:

$\begin{gathered} 2^3=8 \\ 8\text{ outcomes} \end{gathered}$

STEP 2: Find the number of sample spaces for the three tosses

STEP 3: Get the outcomes of the events for which the second toss is tails

Hence, the answers are given as:

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$\lbrace HHH,HHT,HTH,HTT,THH,THT,TTH,TTT\rbrace$

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1 year ago

Are you smarter than a second grader? A random sample of 60 second graders in a certain school district are given a standardized

denis23 [38]

Answer:

We accept H₀ , we do not have enought evidence for rejecting H₀

Step-by-step explanation:

Normal Distribution

sample size n = 60

standard deviation σ = 15

1.Hypothesis Test : Is a one tailed-test on the right

H₀ null hypothesis μ₀ = 50

Hₐ alternative hypothesis μ₀ > 50

2.-We will do the test for a significance level α = 0,01 tht means for a 99% interval of confidence

then z(c) = 2.32

3.- We compute z(s)

z(s) = [ ( μ - μ₀ ) /( σ/√n ) ⇒ z(s) = ( 2 * √60 ) / 15

z(s) = 15.49/15 ⇒ z(s) = 1.033

4.- We compare values of z(c) and z(s)

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Komok [63]

The inequality is

$7- \frac{2}{b}\ \textless \ \frac{5}{b}$

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$\frac{7b}{b} - \frac{2}{b}\ \textless \ \frac{5}{b}$

$\frac{7b-2}{b} \ \textless \ \frac{5}{b}$

$\frac{7b-2}{b}- \frac{5}{b}\ \textless \ 0$

$\frac{7b-2-5}{b}\ \textless \ 0$

$\frac{7b-7}{b}\ \textless \ 0$

$\frac{7(b-1)}{b}\ \textless \ 0$

here b=1 is a root and b=0 is not in the domain of the expression, but it still has an effect in the sign of the expression.

the sign table of $\frac{7(b-1)}{b}$ is :

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that is $\frac{7(b-1)}{b}\ \textless \ 0$ for b∈(0, 1)

Answer: (0, 1)

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