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avanturin [10]
2 years ago
7

Is 0.3 greater that 0.15

Mathematics
2 answers:
valentina_108 [34]2 years ago
8 0

Answer:

yes

Step-by-step explanation:

Simplifying then comparing both terms 0.3and 0.15, 0.3 is greater than

0.15, which means that the first term is greater than the second term.

klemol [59]2 years ago
3 0

Answer:

Yes

Step-by-step explanation:

0.3 means 3 out of ten, or 30 out of 100. 0.15 means 1 and a half out of ten, or 15 out of 100.

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Which expression is equivalent to 73 ⋅ 7−5? 72 77 1 over 7 to the 2nd power 1 over 7 to the 7th power
Rasek [7]

Answer:

  1/7^2

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^-b = 1/a^b

__

Then your expression simplifies to ...

  7^3\cdot 7^{-5}=7^{3-5}=7^{-2}=\boxed{\dfrac{1}{7^2}}

7 0
3 years ago
Read 2 more answers
Number 1 has a picture
MA_775_DIABLO [31]
Question 1

cos(C) = adj/hyp
cos(C) = BC/AC
cos(C) = 15/17

Answer: Choice C) 15/17

=============================================

Question 2

sin(E) = opp/hyp
sin(E) = FD/DE
sin(E) = 24/25

So angle E is the answer

=============================================

Question 3

AC is the adjacent side to the given angle A = 33 degrees
AB = 14 is the hypotenuse

cos(angle) = adjacent/hypotenuse
cos(33) = x/14
14*cos(33) = x
x = 14*cos(33)
x = 11.741
x = 11.7

Answer: 11.7

=============================================

Question 4

x = length of board

cos(angle) = adj/hyp
cos(55) = 6/x
x*cos(55) = 6
x = 6/cos(55)
x = 10.46068
x = 10.5

Answer: 10.5

=============================================

Question 5

112 is the adjacent side to the given angle 62 degrees
x = height of building, which is the opposite leg

tan(angle) = opp/adj
tan(62) = x/112
112*tan(62) = x
x = 112*tan(62)
x = 210.641364
x = 210.6

Answer: 210.6
3 0
3 years ago
The average age of staff in the maths department is 40.
pashok25 [27]

Answer:

Cerian is 28 years old

Step-by-step explanation:

The given parameters are;

The average age of the staffs in the mathematics department = 40

The number of staffs in the department = 7

The average age of Jill, Nicky and Wendy = 41

The average age of Andy, Alan and Cathy = 43

From the given parameters, we have;

The average age of the staffs in the mathematics department = (The sum total of the ages of the members of the math department)/(The number of staffs in the department)

Therefore;

40 = (The sum total of the ages of the members of the math department)/ (7)

From which we have;

The sum total of the ages of the members of the math department = 40 × 7 = 280

Which gives;

Jill's age + Nicky's age + Wendy's age + Cathy's age + Cerian's age + Alan's age + Andy's age = 280 years

The average age of Jill, Nicky and Wendy = 41

Given that Jill, Nicky, and Wendy make up 3 of the 7 members of staffs, we have;

The average age of Jill, Nicky and Wendy = (The sum total of the ages of Jill, Nicky, and Wendy)/(The number of staff Jill, Nicky, and Wendt make)

Therefore;

The sum total of the ages of Jill, Nicky, and Wendy = 41 × 3 = 123

Which gives;

Jill's age + Nicky's age + Wendy's age = 123 years

Similarly, the sum total of the ages of Andy, Alan, and Cathy = 43 × 3 = 129

Which gives;

Andy's age + Alan's age + Cathy's age = 129 years

Therefore;

Cerian's age = (Jill's age + Nicky's age + Wendy's age + Cathy's age + Cerian's age + Alan's age + Andy's age) - (Jill's age + Nicky's age + Wendy's age) + (Andy's age + Alan's age + Cathy's age)

∴ Cerian's age = 280 years - 123 years - 129 years = 28 years

6 0
3 years ago
A different children's party cost £225.50 How many children were at the party?​
Alecsey [184]
Hi, I think you forgot to write a part of the problem, could you write the rest in the comments please. I would be happy to help you
8 0
2 years ago
Can someone help solve?
icang [17]

Answer:

scaning beep no data is acquired

4 0
2 years ago
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