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zhuklara [117]
3 years ago
5

a solution is made by dissolving 14.57 g of sodium bromide nabr in 415 of water . what is the molality of the solution?

Chemistry
2 answers:
jenyasd209 [6]3 years ago
4 0

Answer:

The answer to your question is molality = 0.34

Explanation:

Data

mass of NaBr = 14.57 g

mass of water = 415 g.

molality = ?

Process

1.- Calculate the molar mass of NaBr

NaBr = 23 + 80 = 103 g

2.- Calculate the moles of NaBr

                     103 g of NaBr ------------------ 1 mol

                      14.57 g of NaBr ---------------  x

                               x = (14.57 x 1) / 103

                               x = 14.57 / 103

                               x = 0.141 moles

3.- Calculate the molality

molality = moles / volume

-Substitution

molality = 0.141 / .415

-Result

molality = 0.34

torisob [31]3 years ago
4 0

Answer:

0.341

Explanation:

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