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REY [17]
3 years ago
5

Monique hears on the weather report that cold, dry air from Canada is going to hit warm, moist air from the Gulf of Mexico. She

should expect a:
Chemistry
1 answer:
lara [203]3 years ago
4 0

Answer:

She should suspect a Tornado.

Explanation:

Tornadoes form when warm humid air collides with cold dry air. The denser the cold air is pushed over warm air, causing an updraft. As soon as it reaches the ground a tornado is formed.

You might be interested in
Draw the isotopic notation for an element with 15 protons, 18 neutrons and 18 electrons
tatiyna

Answer:

can't be done

Explanation:

protons and electrons always are the same number,and the neutrons are found by subtracting the atomic mass and protons/electrons soooooooo it can't have 15 protons, 18 electrons, and 18 neutrons.......i hope this helped if not please tell me.

5 0
3 years ago
If 10.0 liters of oxygen at STP are heated to 785.15 °K, what will be the new volume of gas if the pressure is also increased to
Ugo [173]

Answer: The new volume of gas is 28.5 L

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 1.00 atm (at STP)

P_2 = final pressure of gas = 102.6 kPa = 1.01 atm    (1 kPa= 0.0098 atm)

V_1 = initial volume of gas = 10.0 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 273.15K  (STP)

T_2 = final temperature of gas = 785.15K

Now put all the given values in the above equation, we get:

\frac{1.00\times 10.0}{273.15}=\frac{1.01\times V_2}{785.15}

V_2=28.5L

The new volume of gas is 28.5 L

8 0
3 years ago
Estimate ΔG°rxn for the following reaction at 775 K. 2Hg(g) + O2(g) → 2HgO(s) ΔH°= -304.2 kJ; ΔS° = -414.2 J/K
hichkok12 [17]

Answer:

\Delta G^0_{rxn}=16.81kJ

Explanation:

Hello!

In this case, since the Gibbs free energy of any process is related with the enthalpy change, temperature and entropy change as shown below:

\Delta G^0=\Delta H^0-T\Delta S^0

For a chemical reaction it is simply modified to:

\Delta G^0_{rxn}=\Delta H^0_{rxn}-T\Delta S^0_{rxn}

Thus, since the enthalpy of reaction is given as -304.2 kJ and the entropy as -414.2 J/K (-0.4142 kJ/K), at 775 K the Gibbs free energy of reaction turns out:

\Delta G^0_{rxn}=-304kJ-775K*(-0.4142\frac{kJ}{K} )\\\\\Delta G^0_{rxn}=16.81kJ

Whose result means this is a nonspontaneous reaction.

Best regards!

3 0
3 years ago
5.- CONCLUSIONES 1.- ¿Afecta la masa de los cuerpos cuando estos caen?. Explica 2.- ¿Por qué los cuerpos algunos demoraron en ca
otez555 [7]

Answer:

prinjalsunam

Explanation:

9810983488

7 0
2 years ago
How many moles of boron are in 1.39x10^24 atoms
Jobisdone [24]
Ddsdrfvvbgsxvbjfcbbbbhhb
3 0
3 years ago
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