Bohr's
Explanation:
Experimental evidence of Rutherford best supports the Bohr's model of the atom.
Rutherford performed the gold foil experiment in which he bombarded thin gold foil with alpha particles. He found that most of the particles passed through with just few bouncing back.
With this knowledge, he proposed the nuclear model of the atom. The model suggests that an atom is made up of a positively charge dense center and a large space outside where electrons revolves.
- The Bohr's model of the atom was based on quantum mechanics proposed by Planck.
- He assumed the Rutherford's model and suggested that the extranuclear space is made up of electrons in spherical orbits around the nucleus.
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Kinetic energy maybe or something
Answer:
because the water brings a cool breeze when the wind blows
Explanation:
Answer:
The Ka is 9.11 *10^-8
Explanation:
<u>Step 1: </u>Data given
Moles of HX = 0.365
Volume of the solution = 835.0 mL = 0.835 L
pH of the solution = 3.70
<u>Step 2:</u> Calculate molarity of HX
Molarity HX = moles HX / volume solution
Molarity HX = 0.365 mol / 0.835 L
Molarity HX = 0.437 M
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<u>Step 3:</u> ICE-chart
[H+] = [H3O+] = 10^-3.70 = 1.995 *10^-4
Initial concentration of HX = 0.437 M
Initial concentration of X- and H3O+ = 0M
Since the mole ratio is 1:1; there will react x M
The concentration at the equilibrium is:
[HX] = (0.437 - x)M
[X-] = x M
[H3O+] = 1.995*10^-4 M
Since 0+x = 1.995*10^-4 ⇒ x=1.995*10^-4
[HX] = 0.437 - 1.995*10^-4 ≈ 0.437 M
[X-] = x = 1.995*10^-4 M
<u>Step 4: </u>Calculate Ka
Ka = [X-]*[H3O+] / [HX]
Ka = ((1.995*10^-4)²)/ 0.437
Ka = 9.11 *10^-8
The Ka is 9.11 *10^-8
Answer: The value of
is 2
Explanation:
Moles of
= 1.0 mole
Volume of solution = 1.00 L
Initial concentration of
= 
Equilibrium concentration of
=
The given balanced equilibrium reaction is,
Initial conc. 1.0 M 0 M
At eqm. conc. (1.0-x) M (2x) M
The expression for equilibrium constant for this reaction will be,
Given : 2x = 1.0
x= 0.5
Now put all the given values in this expression, we get :

Thus the value of
is 2