This is a mixture problem.
Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.
mass1 * karat1 + mass2*karat = total mass * total carat
Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18
Total mass = 200g.
Total karat = 14.
9*x + 18*(200 -x) = 14*200
9x + 18*200 - 18*x = 14*200
18*200 + 9x - 18x = 14*200
3600 - 9x = 2800
3600 - 2800 = 9x
800 = 9x
9x = 800
x = 800/9
x ≈ 88.89
Therefore 88.89 grams of 9 karat gold must be mixed.
Step-by-step explanation:
see the pic fof the answer
Answer:
68.68
Step-by-step explanation:
for an approximate result, multiply the volume value by 1.057
Answer:
<h2>-11y - 4.1x</h2>
Step-by-step explanation:
Answer:
8/3=2/0.75
Step-by-step explanation:
The variable that you are looking for should be the simplified version of the number on the left.
That is where the 2 would come in. Both numbers should be divided by 4 to gat the answer.
8÷4 = 2
3÷4=0.75
