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3 years ago

13

Help me Assap step by step

1 answer:

Anon25 [30]3 years ago

6 0

Answer: F) 7 mph

<u>Step-by-step explanation:</u>

The line you drew is correct but you read the graph wrong.

The line drawn from 15 hours of training (bottom axis) meets the "line of best fit" at the average running speed (left axis) between 6 and 8, which is 7.

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Please help. Also show how you got it thanks!

Blababa [14]

There are 12 inches in a foot so we can work this problem out in inches 3/5 is 80%......80% of 12 inches is 9.6 inches ....1/4 is 3 inches and 2/3 is 8 inches so we have 9.6,3,and8 now we multiply 9.6*3*8 for the answer to be 230.4 inches squared

8 0

3 years ago

A company manufactures replacement parts for construction cranes. The fixed manufacturing cost is $2,400, and the variable cost

Sergeeva-Olga [200]

The answer is 3704, because, well it depends on his u work it out

3 0

4 years ago

L :V --> W is a linear transformation. Prove each of the following (a) ker L is a subspace of V. (b) range L is a subspace of

iragen [17]

Answer:

a) Assume that $x,y\in\ker L$ , and $\alpha$ is a scalar (a real or complex number).

<em>First. </em>Let us prove that $\ker L$ is not empty. This is easy because $L(0_V)=0_W$ , by linearity. Here, $0_V$ stands for the zero vector of V, and $0_W$ stands for the zero vector of W.

<em>Second.</em> Let us prove that $\alpha x\in\ker L$ . By linearity

$L(\alpha x) = \alpha L(x)=\alpha 0_W=0_W$ .

Then, $\alpha x\in\ker L$ .

<em>Third. </em> Let us prove that $y+ x\in\ker L$ . Again, by linearity

$L(x+y)=L(x)+L(y) = 0_W + 0_W=0_W$ .

And the statement readily follows.

b) Assume that $u$ and $v$ are in range of $L$ . Then, there exist $x,y\in V$ such that $L(x)=u$ and $L(y)=v$ .

<em>First.</em> Let us prove that range of $L$ is not empty. This is easy because $L(0_V)=0_W$ , by linearity.

<em>Second.</em> Let us prove that $\alpha u$ is on the range of $L$ .

$\alpha u = \alpha L(x) = L(\alpha x) = L(z)$ .

Then, there exist an element $z\in V$ such that $L(z)=\alpha u$ . Thus $\alpha u$ is in the range of $L$ .

<em>Third.</em> Let us prove that $u+v$ is in the range of $L$ .

$u+v = L(x)+L(y) = L(x+y)=L(z)$ .

Then, there exist an element $z\in V$ such that $L(z)= u +v$ . Thus $u +v$ is in the range of $L$ .

Notice that in this second part of the problem we used the linearity in the reverse order, compared with the first part of the exercise.

Step-by-step explanation:

6 0

3 years ago

What is the seventh term of the geometric sequence with a first term of 729 and a common ratio of ?

SVEN [57.7K]

<u>Given</u>:

Given that the first term of the geometric sequence is 729.

The common ratio is $\frac{1}{3}$

We need to determine the seventh term of the sequence.

<u>Seventh term</u>:

The seventh term of the sequence can be determined using the formula,

$a_n=a_1(r)^{n-1}$

To find the seventh term, let us substitute n = 7 in the above formula, we get;

$a_7=a_1(r)^{6}$

Now, substituting $a_1= 729$ and $r=\frac{1}{3}$ , we get;

$a_7=729(\frac{1}{3})^{6}$

$a_7=729(\frac{1}{729})$

$a_7=1$

Thus, the seventh term of the geometric sequence is 1.

8 0

3 years ago

Iris wants to buy two necklaces one for your sister and one for self the necklace for her sister cost $42 and the necklace for h

Aloiza [94]

The total including sales tax is $75.60

4 0

3 years ago