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Zolol [24]
3 years ago
13

F(x)=5x-4 g(x)=3x-7 evaluate f(g(3)

Mathematics
2 answers:
dmitriy555 [2]3 years ago
6 0

Answer:

Step-by-step explanation:

f(x)=5x-4 g(x)=3x-7

g(3) = 3(3)-7=2

f(g(3))=f(2) =5(2)-4 = 6

anyanavicka [17]3 years ago
4 0

Answer:

g(3)=9-7=2

f(2)=5×2-4=10-4=6

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The low temperature for 6 days was (-4),(-5),0,(-1),(-6) and 4. What was the average low temperature for those days?
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To find the average add them all up together on a Calculator and divide it by 6
5 0
3 years ago
HELP Find the 29th term of the arithmetic sequence: -13, -6, 1, 8,...
Brilliant_brown [7]

Answer: so the answer is -9 + 23*7 =  152  

Step-by-step explanation:  a24  = a1 + (24-1)d    where a1 = -9 and d = common difference ( 12-5 = 7)  

Hope this helped :D

7 0
3 years ago
A sum of money is placed at simple interest for 3 years at 10% annum and then the amount is invested for 3 years at the same rat
fgiga [73]

Answer:

Initial principal -$300,000

Investment amount after yr 3-$390,000

Final investment amount, after 6 yrs-$519,090

Step-by-step explanation:

Let X be the amount initially invested.

#The amount after 3 yrs of simple interest is calculated as:

I=PRT\\\\A=P+I\\\\A=X+X\times 0.1\times 3\\\\A=1.3X

#The amount after 5 yrs is calculated by compounding the amount after 3 yrs for 2 yrs at 10%:

A=P(1+i)^2\\\\471900=1.3X(1.1)^2\\\\471900=1.573X\\\\X=300000

Hence, the amount initially invested as $300,000

#Amount of invested after 6 yrs is therefore:

A=P(1+i)^n\\\\=471900\times1.1\\\\=519090

Hence, the total amount of the investment after 6 yrs is $519,090

#Substitute X in simple interest equation to find amount after 3 yrs of simple interest:

I=PRT\\\\A=P+I\\\\A=X+X\times 0.1\times 3\\\\A=1.3X\\\\=1.3\times 300000\\\\=390000

Hence, the total amount of the investment after first 3 yrs is $390,000

3 0
4 years ago
How many times does 16 go in 41
charle [14.2K]
41/16
=2.5625
so it goes into 41 2 times
4 0
4 years ago
What is the probability of having 53 Sunday in the year 2024​
irina1246 [14]

Answer:

here in ques it is not specifically said that the year is leap year or non leap year . so i am writing the answer for both conditions.

considering a non leap year

see we have 365 days in a non-leap year.

52 weeks and one extra day= 365 days

52 weeks means definitely there are 52 sundays (this is true for all other days also).

that means if the extra day comes out to be sunday then we will have 53 sundays.

so now the ques boils down to what is the prob of this extra day to be a sunday .

this extra one day can be {monday or tuesday or wednesday or thursday or friday or saturday or sunday }= samplespace (s)

i.e n(s) = 7

so prob of this extra one day to be a sunday is 1/7.

[note - this is also the answer for having 53 mondays or 53 tuesdays or 53 wednesdays or 53 thursdays or 53 fridays or 53 saturdays.]

considering a leap year

leap year contains 366 days

52 weeks plus two two extra days

52 weeks means definitely there are 52 sundays (this is true for all other days also).

if either of these two is sunday then we will have 53 sundays

these two days can be {mon, tue} or { tue , wed} or { wed , thurs} or {thurs , fri} or { fri, sat} or { sat , sun} or {sun , mon} i.e total =7

out of these only two outcomes i.e { sat , sun} and {sun , mon} is having sunday with them .

so our desired prob is 2/7.

Step-by-step explanation:

8 0
3 years ago
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